ÌâÄ¿ÄÚÈÝ

15£®ÔÚij´Î¡°20Ã×ÕÛ·µÅÜ¡±²âÊÔÖУ¬ÊÜÊÔÕßÔÚÆ½Ö±ÅܵÀÉÏÌýµ½¡°ÅÜ¡±µÄ¿ÚÁîºó£¬ÔÚÆðµãÖÕµãÏßǰȫÁ¦ÅÜÏòÕýǰ·½20Ã×´¦µÄÕÛ·µÏߣ¬²âÊÔԱͬʱ¿ªÊ¼¼ÆÊ±£®ÊÜÊÔÕßµ½´ïÕÛ·µÏßʱ£¬ÓÃÊÖ´¥ÃþÕÛ·µÏß´¦µÄÎïÌ壨ÈçľÏ䣩£¬ÔÙתÉíÅÜÏòÆðµãÖÕµãÏߣ¬µ±Ðز¿µ½´ïÆðµãÖÕµãÏߵĴ¹Ö±ÃæÊ±£¬²âÊÔԱͣ±í£¬Ëù¼ÆÊ±¼ä¼´Îª¡°ÕÛ·µÅÜ¡±µÄ³É¼¨£¬ÈçͼËùʾ£®ÉèÊÜÊÔÕ߯ðÅܵļÓËÙ¶ÈΪ4.0m/s2£¬Ô˶¯¹ý³ÌÖеÄ×î´óËÙ¶ÈΪ6.4m/s£¬µ½´ïÕÛ·µÏß´¦Ê±Ðè¼õËÙµ½Á㣬¼ÓËٶȵĴóСΪ8.0m/s2£¬·µ»ØÊ±´ïµ½×î´óËٶȺó²»Ðè¼õËÙ£¬±£³Ö×î´óËٶȳåÏߣ®ÊÜÊÔÕßÔÚ¼ÓËٺͼõËٽ׶εÄÔ˶¯¾ù¿ÉÊÓΪÔȱäËÙÖ±ÏßÔ˶¯£®Çó¸ÃÊÜÊÔÕß¡°ÕÛ·µÅÜ¡±µÄ³É¼¨Îª¶àÉÙÃ룿

·ÖÎö ¸ù¾ÝÔȱäËÙÖ±ÏßÔ˶¯µÄËÙ¶ÈÎ»ÒÆ¹«Ê½Çó³öÔȼÓËÙÔ˶¯ºÍÔȼõËÙÔ˶¯µÄÎ»ÒÆ£¬´Ó¶øµÃ³öÔÈËÙÔ˶¯µÄÎ»ÒÆ£¬Çó³öÔÈËÙÔ˶¯µÄʱ¼ä£¬½áºÏËÙ¶Èʱ¼ä¹«Ê½Çó³öÔȼÓËÙºÍÔȼõËÙÔ˶¯µÄʱ¼ä£¬×¥×¡·µ»Ø10mºÍǰ10mµÄÔ˶¯Çé¿öÏàͬ£¬Çó³ö×Üʱ¼ä£®

½â´ð ½â£º¶ÔÊÜÊÔÕߣ¬ÓÉÆðµãÖÕµãÏßÏòÕÛ·µÏßÔ˶¯µÄ¹ý³ÌÖУ»
¼ÓËٽ׶Σº${t}_{1}=\frac{{v}_{m}}{{a}_{1}}=\frac{6.4}{4}s=1.6s$¡­¢Ù
${x}_{1}=\frac{1}{2}{v}_{m}{t}_{1}=\frac{1}{2}¡Á6.4¡Á1.6m=5.12m$¡­¢Ú
¼õËٽ׶Σº${t}_{3}=\frac{{v}_{m}}{{a}_{2}}=\frac{6.4}{8}s=0.8s$¡­¢Û
${x}_{3}=\frac{{v}_{m}}{2}{t}_{3}=\frac{6.4}{2}¡Á0.8m=2.56m$¡­¢Ü
ÔÈËٽ׶Σº${t}_{2}=\frac{l-£¨{x}_{1}+{x}_{3}£©}{{v}_{m}}=\frac{20-£¨5.12+2.56£©}{6.4}s=1.925s$¡­¢Ý
ÓÉÕÛ·µÏßÏòÆðµãÖÕµãÏßÔ˶¯µÄ¹ý³ÌÖÐ
¼ÓËٽ׶Σº
t4=t1=1.6s£¬¡­¢Þ
x4=x1=5.12m¡­¢ß
ÔÈËٽ׶Σº${t}_{5}=\frac{l-{x}_{4}}{{v}_{m}}=\frac{20-5.12}{6.4}s=2.325s$¡­¢à
ÊÜÊÔÕß¡°ÕÛ·µÅÜ¡±µÄ³É¼¨Îª£º
t=t1+t2+t3+t4+t5=8.25s
´ð£º¸ÃÊÜÊÔÕß¡°ÕÛ·µÅÜ¡±µÄ³É¼¨Îª8.25s£®

µãÆÀ ½â¾ö±¾ÌâµÄ¹Ø¼üÀíÇåÕû¸ö¹ý³ÌÖеÄÔ˶¯¹æÂÉ£¬½áºÏÔ˶¯Ñ§¹«Ê½Áé»îÇó½â£¬ÄѶȲ»´ó£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø