ÌâÄ¿ÄÚÈÝ

10£®Í¼Ê¾ÊÇÓÃÆµÂÊΪ50HzµÄ´òµã¼ÆÊ±Æ÷´òϵÄÖ½´ø£¬A¡¢B¡¢C¡¢DÒÀ´ÎΪֽ´øÉÏÑ¡³öµÄ¼ÆÊýµã£®
£¨1£©¸ù¾Ý±ê³öµÄÊý¾Ý£¬´òµã¼ÆÊ±Æ÷´òA¡¢CÁ½¼ÆÊýµãµÄʱ¼ä¼ä¸ôΪ0.2s£¬´òB¡«DµãµÄ¹ý³ÌÖУ¬Ö½´øµÄƽ¾ùËÙ¶È´óСΪ0.431m/s£®
£¨2£©´òµã¼ÆÊ±Æ÷´òA¡«DµãµÄ¹ý³ÌÖУ¬Ö½´øµÄÔ˶¯Çé¿öÊÇD£¨ÌîÕýÈ·Ñ¡ÏîǰµÄ×Öĸ£©£®

A£®Ò»Ö±×ö¼ÓËÙÔ˶¯                B£®Ò»Ö±×ö¼õËÙÔ˶¯
C£®ÏÈ×ö¼õËÙÔ˶¯ºó×ö¼ÓËÙÔ˶¯       D£®×ö¼ÓËÙÔ˶¯ºó×ö¼õËÙÔ˶¯£®

·ÖÎö £¨1£©¸ù¾ÝƵÂÊΪ50Hz£¬¼°¹«Ê½T=$\frac{1}{f}$£¬¼´¿ÉÇóµÃʱ¼ä¼ä¸ô£¬¸ù¾Ýƽ¾ùËٶȵ͍ÒåµÃ³öBD¶ÎµÄƽ¾ùËÙ¶È´óС£»
£¨2£©¸ù¾ÝÖ½´øÉÏÁ¬ÐøÏàµÈʱ¼äÄÚÎ»ÒÆµÄ±ä»¯£¬¿ÉÒÔÅжÏС³µµÄÔ˶¯ÐÔÖÊ£®

½â´ð ½â£º£¨1£©ÆµÂÊΪ50Hz£¬ÄÇô´òµã¼ÆÊ±Æ÷´òA¡¢CÁ½¼ÆÊýµãµÄʱ¼ä¼ä¸ôΪt=10¡Á0.02=0.2s£»
¸ù¾Ý¹«Ê½$\overline{v}$=$\frac{{x}_{BD}}{{t}_{BD}}$=$\frac{0.1212-0.035}{0.2}$=0.431m/s£®
£¨2£©ÓÉÖ½´ø¿ÉÖª£¬ÏàÁÚ¼ÆÊýµãÄÚµÄÎ»ÒÆÏÈÔ½À´Ô½´ó£¬ºóÔ½À´Ô½Ð¡£¬Òò´ËС³µÏȼÓËÙÔ˶¯£¬ºó¼õËÙÔ˶¯£¬¹ÊABC´íÎó£¬DÕýÈ·£®
¹Ê´ð°¸Îª£º£¨1£©0.2£¬0.431£»£¨2£©D£®

µãÆÀ ÒªÌá¸ßÓ¦ÓÃÔȱäËÙÖ±ÏߵĹæÂÉÒÔ¼°ÍÆÂÛ½â´ðʵÑéÎÊÌâµÄÄÜÁ¦£¬ÔÚÆ½Ê±Á·Ï°ÖÐÒª¼ÓÇ¿»ù´¡ÖªÊ¶µÄÀí½âÓëÓ¦Óã®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø