ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÈçͼËùʾ£¬Ò»¿é³¤Îª L = 1 m£¬ÖÊÁ¿Îª M = 1.2 kg µÄľ°å·ÅÖÃÔÚˮƽµØÃæÉÏ£¬Ò»ÖÊÁ¿ m = 0.4 kg µÄ СÎï¿éÒÔ v0 = 2 m / s µÄËÙ¶È´Ó×ó¶Ë»¬ÉÏľ°å£¬ÒÑ֪СÎï¿éÓëľ°å×ó°ë²¿·ÖºÍÓҰ벿·Ö¼äµÄ¶¯Ä¦²ÁÒòÊý·Ö±ðΪ= 0.3£¬= 0.7£¬Ä¾°åÓëµØÃæ¼äµÄ¶¯Ä¦²ÁÒòÊý= 0.1£¬ÖØÁ¦¼ÓËÙ¶È g = 10 m / s2¡£ÊÔÇó£º

£¨1£©Ð¡Îï¿é»¬µ½³¤Ä¾°åÖеãʱËÙ¶È v µÄ´óС¡£

£¨2£©Ð¡Îï¿éÄÜ·ñ´Óľ°åÉÏ»¬Âä¡£

¡¾´ð°¸¡¿£¨1£©1m/s£¨2£©²»ÄÜ

¡¾½âÎö¡¿

Îï¿éÔÚľ°å×ó²àÔ˶¯Ê±£ºËüÓëľ°å¼äµÄĦ²ÁÁ¦

ľ°åÓëµØÃæ¼äµÄ×î´ó¾²Ä¦²ÁÁ¦

<¹Ê´Ëʱľ°å²»¶¯£»

ÉèÎï¿éµ½´ïľ°åÖеãʱµÄËÙ¶ÈΪ

½âµÃ

Îï¿éÔÚľ°åÓÒ²àÔ˶¯Ê±£ºËüÓëľ°å¼äµÄĦ²ÁÁ¦

>¹Êľ°å¿ªÊ¼Ô˶¯

Îï¿éÓëľ°å¼ÓËÙ¶È´óС·Ö±ðΪ ¡¢

½âµÃ£º

½âµÃ

Á½ÕßËÙ¶ÈÏàµÈÐèÒªµÄʱ¼äΪ£¬ÏàµÈµÄËÙ¶È´óСΪ

·¨Ò»£ºÎï¿é·¢ÉúµÄÎ»ÒÆ

ľ°å·¢ÉúµÄÎ»ÒÆ

<0.5m ËùÒÔ²»»á»¬Âä

·¨¶þ£º

<0.5m

ËùÒÔ²»»á»¬Âä

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿£¨1£©ÔÚ×öÓôòµã¼ÆÊ±Æ÷²âËٶȵÄʵÑéʱ£¬ÒªÓõ½´òµã¼ÆÊ±Æ÷£¬´òµã¼ÆÊ±Æ÷ÊÇÒ»ÖÖ¼ÆÊ±ÒÇÆ÷£¬ÆäµçԴƵÂÊΪ50 Hz£¬³£Óõġ°µç´Å´òµã¼ÆÊ±Æ÷¡±Ê¹ÓõĵçѹÊÇ__________VµÄ________(Ìî¡°Ö±Á÷µç¡±»ò¡°½»Á÷µç¡±)£¬Ëüÿ¸ô________s´òÒ»¸öµã¡£

£¨2£©½Óͨ´òµã¼ÆÊ±Æ÷µçÔ´ºÍÈÃÖ½´ø¿ªÊ¼Ô˶¯£¬ÕâÁ½¸ö²Ù×÷Ö®¼äµÄʱ¼ä˳Ðò¹ØÏµÊÇ£¨____£©

A£®ÏȽÓͨµçÔ´£¬ÔÙÈÃÖ½´øÔ˶¯

B£®ÏÈÈÃÖ½´øÔ˶¯£¬ÔÙ½ÓͨµçÔ´

C£®ÈÃÖ½´øÔ˶¯µÄͬʱ½ÓͨµçÔ´

D£®ÏÈÈÃÖ½´øÔ˶¯»òÏȽÓͨµçÔ´¶¼¿ÉÒÔ

£¨3£©Ä³Í¬Ñ§ÔÚ¡°Óôòµã¼ÆÊ±Æ÷²âËÙ¶È¡±µÄʵÑéÖУ¬Óôòµã¼ÆÊ±Æ÷¼Ç¼Á˱»Ð¡³µÍ϶¯µÄÖ½´øµÄÔ˶¯Çé¿ö£¬ÔÚÖ½´øÉÏÈ·¶¨³öA¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¹²7¸ö¼ÆÊýµã.ÏàÁÚ¼ÆÊýµã¼äµÄ¾àÀëÈçͼËùʾ£¬Ã¿Á½¸öÏàÁڵļÆÊýµãÖ®¼äµÄʱ¼ä¼ä¸ôΪ0.10 s.(±¾Ìâ¼ÆËã½á¹û¾ù±£Áô3λÓÐЧÊý×Ö)

ÊÔ¸ù¾ÝÖ½´øÉϸ÷¸ö¼ÆÊýµã¼äµÄ¾àÀ룬ÿ¸ô0.10 s²âÒ»´ÎËÙ¶È£¬¼ÆËã³ö´òÏÂBµãʱС³µµÄ˲ʱËÙ¶È£¬²¢½«´ËËÙ¶ÈÖµÌîÈëϱí.

vB

vC

vD

vE

vF

ÊýÖµ(m/s)

______

0.479

0.560

0.640

0.721

£¨4£©ÏÖC¡¢D¡¢E¡¢F¸÷¸öʱ¿ÌµÄ˲ʱËÙ¶ÈÒѱêÔÚÏÂͼֱ½Ç×ø±êϵÖУ¬Çë°ÑÄã¼ÆËã³öBµãµÄ˲ʱËٶȱê¼ÇÔÚͼÖв¢»­³öС³µµÄ˲ʱËÙ¶ÈËæÊ±¼ä±ä»¯µÄ¹ØÏµÍ¼Ïß.

£¨______£©

£¨5£©¸ù¾ÝͼÏñ¼ÆËã³öС³µµÄ¼ÓËÙ¶È__________¡££¨½á¹û±£Áô3λÓÐЧÊý×Ö£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø