ÌâÄ¿ÄÚÈÝ

18£®Ä³Í¬Ñ§ÎªÌ½ÔÂÓԱÉè¼ÆÁËÈçÏÂʵÑ飺ÔÚÔÂÇò±íÃæÒÔ³õËÙ¶Èv0ˮƽÅ׳öÒ»¸öÎïÌå²â³ö¸ÃÎïÌåµÄÊúÖ±Î»ÒÆÎªh£¬Ë®Æ½Î»ÒÆÎªx£®Í¨¹ý²éÔÄ×ÊÁÏÖªµÀÔÂÇòµÄ°ë¾¶ÎªR£¬ÒýÁ¦³£Á¿ÎªG£®¸ù¾ÝÉÏÊöÐÅÏ¢¿ÉÇó³öµÄÎïÀíÁ¿ÊÇ£¨¡¡¡¡£©
A£®ÔÂÇòµÄµÚÒ»ÓîÖæËÙ¶ÈB£®ÎïÌåÓëÔÂÇòÖ®¼äµÄÒýÁ¦
C£®ÔÂÇò±íÃæµÄÖØÁ¦¼ÓËÙ¶ÈD£®ÔÂÇòµÄÖÊÁ¿

·ÖÎö ÓÉÅ׳öÎïÌåµÄˮƽ¡¢ÊúÖ±·½ÏòµÄÎ»ÒÆ¹ØÏµ¿ÉÇóµÃÔÂÇò±íÃæµÄÖØÁ¦¼ÓËÙ¶È£»ÓÉÍòÓÐÒýÁ¦³äµ±ÏòÐÄÁ¦¿ÉÅжϸ÷ÎïÀíÁ¿ÄÜ·ñÇó³ö£®

½â´ð ½â£ºÎïÌåˮƽÅ׳öºó£¬Ë®Æ½·½Ïòx=v0t£»
h=$\frac{1}{2}$gt2£»
ÁªÁ¢½âµÃ£º
g=$\frac{2h{v}_{0}^{2}}{{x}^{2}}$£» ¹ÊÖØÁ¦¼ÓËÙ¶È¿ÉÇó£»¹ÊCÕýÈ·£»
ÓÉÓÚ²»ÖªÎïÌåµÄÖÊÁ¿£¬¹ÊÎïÌåÊܵ½µÄÒýÁ¦²»¿ÉÇ󣬹ÊB´íÎó£»
¶øÓÉmg=m$\frac{{v}^{2}}{r}$¿ÉÖª£¬µÚÒ»ÓîÖæËÙ¶Èv=$\sqrt{gr}$£¬¹ÊAÕýÈ·£»
ÓÉG$\frac{Mm}{{R}^{2}}$=m$\frac{{v}^{2}}{r}$¿ÉÇóµÃÔÂÇòµÄÖÊÁ¿£¬µ«ÎÞ·¨Çó³öÎïÌåµÄÖÊÁ¿£¬¹ÊDÕýÈ·£»
¹ÊÑ¡£ºACD£®

µãÆÀ Ó¦ÓÃÍòÓÐÒýÁ¦¶¨Âɽâ¾öÌìÌåÔ˶¯Ê±£¬×¢ÒâÖ»ÄÜÇó³öÖÐÐÄÌìÌåµÄÖÊÁ¿£»Í¬Ê±×¢ÒâµÚÒ»ÓîÖæËٶȵ͍ÒåΪ°ë¾¶ÎªÐÇÇò°ë¾¶Ê±µÄÎÀÐÇÔËÐÐËÙ¶È£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø