题目内容
设x∈R,向量
=(2,x),
=(3,-2),且
⊥
,则|
-
|=______.
| a |
| b |
| a |
| b |
| a |
| b |
∵
⊥
,∴
•
=0,即2×3-2x=0,解得x=3,
∴
-
=(2,3)-(3,-2)=(-1,5),
则|
-
|=
=
.
故答案为:
.
| a |
| b |
| a |
| b |
∴
| a |
| b |
则|
| a |
| b |
| 1+52 |
| 26 |
故答案为:
| 26 |
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=(1,x-1),
=(x+1,3),若
∥
,则实数x等于( )
| a |
| b |
| a |
| b |
| A、2 | ||
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| C、2或-2 | ||
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