题目内容
函数y=sin2x+cos2x(x∈[0,
])的值域为______.
| π |
| 2 |
∵y=sin2x+cos2x
=
sin(2x+
),
∵x∈[0,
],
∴2x+
∈[
,
],
∴y∈[-1,
],
故答案为:【-1
】
=
| 2 |
| π |
| 4 |
∵x∈[0,
| π |
| 2 |
∴2x+
| π |
| 4 |
| π |
| 4 |
| 5π |
| 4 |
∴y∈[-1,
| 2 |
故答案为:【-1
| 2 |
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题目内容
| π |
| 2 |
| 2 |
| π |
| 4 |
| π |
| 2 |
| π |
| 4 |
| π |
| 4 |
| 5π |
| 4 |
| 2 |
| 2 |