题目内容
log2cos
+log2cos
+log2cos
的值为______．
| π |
| 9 |
| 2π |
| 9 |
| 4π |
| 9 |
log2cos
+log2cos
+log2cos
=log2cos
cos
cos
=log2
=log2
=-3
故答案为：-3
| π |
| 9 |
| 2π |
| 9 |
| 4π |
| 9 |
=log2cos
| π |
| 9 |
| 2π |
| 9 |
| 4π |
| 9 |
=log2
8sin
| ||||||||
8sin
|
=log2
| 1 |
| 8 |
=-3
故答案为：-3
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