题目内容
已知|
|=10,|
|=12,
与
的夹角为120°,求:
(1)
•
;
(2)(3
-2
)•(4
+
).
| a |
| b |
| a |
| b |
(1)
| a |
| b |
(2)(3
| b |
| a |
| a |
| b |
(1)
•
=|
||
|cos120°=10×12×(-
)=-60; …(6分)
(2)(3
-2
)•(4
+
)=-8|
|2+10
•
+3|
|2=-8×100+10×(-60)+3×122=-968…(12分)
| a |
| b |
| a |
| b |
| 1 |
| 2 |
(2)(3
| b |
| a |
| a |
| b |
| a |
| a |
| b |
| b |
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