题目内容
已知命题p:?x1,x2∈R,(f(x2)-f(x1))(x2-x1)≥0,则?p是( )
A.?x1,x2∈R,(f(x2)-f(x1))(x2-x1)≤0
B.?x1,x2∈R,(f(x2)-f(x1))(x2-x1)≤0
C.?x1,x2∈R,(f(x2)-f(x1))(x2-x1)<0
D.?x1,x2∈R,(f(x2)-f(x1))(x2-x1)<0
C
【解析】
因为全称命题p: ?x∈M, p(x)的否定?p是特称命题: ?x0∈M, ?p(x0)
所以?p: ?x1,x2∈R,(f(x2)-f(x1))(x2-x1)<0
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