题目内容
若
=1,则
=( )
| lim |
| x→1 |
| f(x-1) |
| x-1 |
| lim |
| x→1 |
| x-1 |
| f(2-2x) |
| A、-1 | ||
| B、1 | ||
C、-
| ||
D、
|
分析:利用题设条件,由
=-
,能求出其结果.
| lim |
| x→1 |
| x-1 |
| f(2-2x) |
| 1 |
| 2 |
| lim |
| x→1 |
| 2-2x |
| f(2-2x) |
解答:解:若
=1,则
=-
=-
×1=-
.
故选C.
| lim |
| x→1 |
| f(x-1) |
| x-1 |
| lim |
| x→1 |
| x-1 |
| f(2-2x) |
| 1 |
| 2 |
| lim |
| x→1 |
| 2-2x |
| f(2-2x) |
| 1 |
| 2 |
| 1 |
| 2 |
故选C.
点评:本题考查函数的极限和运算,解题时要注意合理地进行等价转换.
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