题目内容
已知向量
=(1,2),
=(-1,3),
∥
且
≠
,则
与
的夹角是( )
| a |
| b |
| c |
| a |
| c |
| 0 |
| c |
| b |
| A.0 | B.π | C.
| D.
|
∵
∥
且
≠
,
=(1,2)
∴可设
=λ(1,2),λ≠0,
得|
|=
=
|λ|
∵|
|=
=
,
•
=λ×(-1)+2λ×3=5λ
∴满足cosθ=
=
=±
∵θ∈[0,π],∴θ=
或
故选:D
| c |
| a |
| c |
| 0 |
| a |
∴可设
| c |
得|
| c |
| λ2(1+4) |
| 5 |
∵|
| b |
| (-1)2+32 |
| 10 |
| c |
| b |
∴满足cosθ=
| ||||
|
|
| 5λ | ||||
|
| ||
| 2 |
∵θ∈[0,π],∴θ=
| π |
| 4 |
| 3π |
| 4 |
故选:D
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