题目内容
已知
(
-an-b)=1，求实数a，b的值．
| lim |
| n→∞ |
| n2+1 |
| n+1 |
| lim |
| n→∞ |
| n2+1 |
| n+1 |
| lim |
| n→∞ |
| n2+1-an2-an- bn-b |
| n+1 |
=
| lim |
| n→∞ |
| (1-a)n2-(a+b)n+1-b |
| n+1 |
∴1-a=0且-（a+b）=1
解得a=1，b=-2
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=
∴1-a=0且-（a+b）=1
解得a=1，b=-2
题目内容
| lim |
| n→∞ |
| n2+1 |
| n+1 |
| lim |
| n→∞ |
| n2+1 |
| n+1 |
| lim |
| n→∞ |
| n2+1-an2-an- bn-b |
| n+1 |
| lim |
| n→∞ |
| (1-a)n2-(a+b)n+1-b |
| n+1 |