题目内容

求下列函数的导数:
(1)y=x2sinx;
(2)y=ln(x+
1+x2
);
(3)y=
ex+1
ex-1
;
(4)y=
x+cosx
x+sinx
.
(1)y′=(x2)′sinx+x2(sinx)′=2xsinx+x2cosx.
(2)y′=
1
x+
1+x2
•(x+
1+x2
)′
=
1
x+
1+x2
(1+
x
1+x2
)
=
1
1+x2
.
(3)y′=
(ex+1)′(ex-1)-(ex+1)(ex-1)′
(ex-1)2

=
-2ex
(ex-1)2
.
(4)y′=
(x+cosx)′(x+sinx)-(x+cosx)(x+sinx)′
(x+sinx)2

=
(1-sinx)(x+sinx)-(x+cosx)(1+cosx)
(x+sinx)2

=
-xcosx-xsinx+sinx-cosx-1
(x+sinx)2
.
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