题目内容
已知cos(75°+α)=
解析:cos(105°-α)=cos[180°-(75°+α)]=-cos(75°+α)=-
,
sin(α-105°)=-sin(105°-α)=-sin[180°-(75°+α)]=-sin(75°+α).
由已知可知角75°+α为第四象限角,则有
sin(75°+α)=
=-
.
则cos(105°-α)+sin(α-105°)=-
+
=
.
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题目内容
已知cos(75°+α)=
解析:cos(105°-α)=cos[180°-(75°+α)]=-cos(75°+α)=-
,
sin(α-105°)=-sin(105°-α)=-sin[180°-(75°+α)]=-sin(75°+α).
由已知可知角75°+α为第四象限角,则有
sin(75°+α)=
=-
.
则cos(105°-α)+sin(α-105°)=-
+
=
.