题目内容
若数列{an}满足a1=3,a2=4,且an=
(n≥3),则a2007的值为( )
| an-1 |
| an-2 |
分析:利用已知经过计算得出周期性an+6=an即可得出.
解答:解:∵数列{an}满足a1=3,a2=4,且an=
(n≥3),
∴a3=
=
,a4=
=
,a5=
=
,a6=
=
,a7=3,a8=4,
…,
∴an+6=an.
∴a2007=a334×6+3=a3=
.
故选D.
| an-1 |
| an-2 |
∴a3=
| a2 |
| a1 |
| 4 |
| 3 |
| a3 |
| a2 |
| 1 |
| 3 |
| a4 |
| a3 |
| 1 |
| 4 |
| a5 |
| a4 |
| 3 |
| 4 |
…,
∴an+6=an.
∴a2007=a334×6+3=a3=
| 4 |
| 3 |
故选D.
点评:经过计算得出周期性an+6=an是解题的关键.
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