题目内容
已知函数f(
)=
,则( )
| 1 |
| x |
| x |
| 1-x |
A.f(
| B.f(
| C.f(
| D.f(
|
∵f(
)=
=
∴f(x)=
∴-f(x)=-
,f(
)+1=
+1=
=-
∴f(
)+1=-f(x)
故选D
| 1 |
| x |
| x |
| 1-x |
| 1 | ||
|
∴f(x)=
| 1 |
| x-1 |
∴-f(x)=-
| 1 |
| x-1 |
| 1 |
| x |
| x |
| 1-x |
| 1 |
| 1-x |
| 1 |
| x-1 |
∴f(
| 1 |
| x |
故选D
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已知函数f(
)=
,则( )
| 1 |
| x |
| x |
| 1-x |
A、f(
| ||||
B、f(
| ||||
C、f(
| ||||
D、f(
|