题目内容
如图所示,△ABC的重心为G,O为坐标原点,
![]()
解:如图,设AG交BC于点M,则M是BC的中点.
=b-a,
=c-a,
=c-b,
=
+![]()
=b-a+
(c-b)=
(c+b-2a),
![]()
=
(c+b-2a),
所以
=
+
=a+
(c+b-2a)=
(a+b+c).
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题目内容
如图所示,△ABC的重心为G,O为坐标原点,
![]()
解:如图,设AG交BC于点M,则M是BC的中点.
=b-a,
=c-a,
=c-b,
=
+![]()
=b-a+
(c-b)=
(c+b-2a),
![]()
=
(c+b-2a),
所以
=
+
=a+
(c+b-2a)=
(a+b+c).