Question

lim

n→∞

(

n2+1

n+1

-an-b)=0，则a=______，b=______．

Answer 1

∵

lim

n→∞

(

n2+1-an2-bn-an-b

n+1

)=

lim

n→∞

(

(1-a)n2-(b+a)n+1-b

n+1

)=0，
∴1-a=0，a+b=0
∴a=1，b=-1
故答案为  1；-1