题目内容
求极限| lim |
| n→∞ |
| x |
| x+1 |
| x |
分析:把
(
-
).转化为
,由此能够求出
(
-
).
| lim |
| n→∞ |
| x |
| x+1 |
| x |
| lim |
| n→∞ |
| ||||||||||
|
| lim |
| n→∞ |
| x |
| x+1 |
| x |
解答:解:原式=
=
=
=
.
| lim |
| n→∞ |
| ||||||||||
|
=
| lim |
| n→∞ |
| ||||
|
| lim |
| n→∞ |
| 1 | ||||
|
| 1 |
| 2 |
点评:本题考查极限的求法和应用,解题时要认真审题,仔细思考,注意培养计算能力.
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