题目内容
计算:
(1)(0.064)-
-(-
)°+[(-2)3]-
+16-0.75+|-0.01|
;
(2)log2732•log6427+log92•log4
.
(1)(0.064)-
| 1 |
| 3 |
| 7 |
| 8 |
| 4 |
| 3 |
| 1 |
| 2 |
(2)log2732•log6427+log92•log4
| 27 |
(1)(0.064)-
-(-
)0+[(-2)3]-
+16-0.75+|-0.01|
=(
)
-1+(-2)-4+(24)-
+0.1
=((
)3)
-1+
+
+
=
-1+
+
+
=
.
(2)log2732•log6427+log92•log4
=
•
+
•
=
+
•
=
+
=
.
| 1 |
| 3 |
| 7 |
| 8 |
| 4 |
| 3 |
| 1 |
| 2 |
=(
| 1000 |
| 64 |
| 1 |
| 3 |
| 3 |
| 4 |
=((
| 10 |
| 4 |
| 1 |
| 3 |
| 1 |
| 16 |
| 1 |
| 8 |
| 1 |
| 10 |
=
| 5 |
| 2 |
| 1 |
| 16 |
| 1 |
| 8 |
| 1 |
| 10 |
=
| 143 |
| 80 |
(2)log2732•log6427+log92•log4
| 27 |
=
| lg32 |
| lg27 |
| lg27 |
| lg64 |
| lg2 |
| lg9 |
lg
| ||
| lg4 |
=
| lg25 |
| lg26 |
| lg2 |
| lg32 |
lg3
| ||
| lg22 |
=
| 5 |
| 6 |
| 3 |
| 8 |
=
| 29 |
| 24 |
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