题目内容
已知向量|
|=1,|
|=
.
(Ⅰ)若向量
,
的夹角为60°,求
•
的值;
(Ⅱ)若|
+
|=
,求
•
的值;
(Ⅲ)若
•(
-
)=0,求
,
的夹角.
| a |
| b |
| 2 |
(Ⅰ)若向量
| a |
| b |
| a |
| b |
(Ⅱ)若|
| a |
| b |
| 5 |
| a |
| b |
(Ⅲ)若
| a |
| a |
| b |
| a |
| b |
(I)当向量
,
的夹角为60°时,
求
•
=
•
cos60°=
;
(II)∵|
|=1,|
|=
.
∴由|
+
|=
,得(
+
)2=1+2
•
+2=5
解之得
•
=1;
(III)∵
•(
-
)=
2-
•
=0
∴
•
=
2=1,设
,
的夹角为α
则cosα=
=
,可得α=
.
| a |
| b |
求
| a |
| b |
| |a| |
| |b| |
| ||
| 2 |
(II)∵|
| a |
| b |
| 2 |
∴由|
| a |
| b |
| 5 |
| a |
| b |
| a |
| b |
解之得
| a |
| b |
(III)∵
| a |
| a |
| b |
| a |
| a |
| b |
∴
| a |
| b |
| a |
| a |
| b |
则cosα=
| ||||
|
| ||
| 2 |
| π |
| 4 |
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