题目内容
2.设A={(x,y)|y=3x+2},B={(x,y)|y=x2+6x+4},求A∩B.分析 联立方程组$\left\{\begin{array}{l}y=3x+2\\{y=x}^{2}+6x+4\end{array}\right.$,求解即可.
解答 解:由$\left\{\begin{array}{l}y=3x+2\\{y=x}^{2}+6x+4\end{array}\right.$得:$\left\{\begin{array}{l}x=-1\\ y=-1\end{array}\right.$,或$\left\{\begin{array}{l}x=-2\\ y=-4\end{array}\right.$,
A∩B={(-1,-1),(-2,-4)}
点评 本题考查集合的交集的求法,基本知识的考查.
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