题目内容
比较下列数的大小:cos
,-cos
,sin
从小到大的顺序是______.
| 3 |
| 2 |
| 7 |
| 4 |
| 1 |
| 10 |
由题意-cos
=cos(π-
),sin
=cos(
-
)
∵0<π-
<
-
<
<
,余弦函数在(0,
)上单调递减,
∴cos(π-
)>cos(
-
)>cos
∴cos
<sin
<-cos
故答案为:cos
<sin
<-cos
| 7 |
| 4 |
| 7 |
| 4 |
| 1 |
| 10 |
| π |
| 2 |
| 1 |
| 10 |
∵0<π-
| 7 |
| 4 |
| π |
| 2 |
| 1 |
| 10 |
| 3 |
| 2 |
| π |
| 2 |
| π |
| 2 |
∴cos(π-
| 7 |
| 4 |
| π |
| 2 |
| 1 |
| 10 |
| 3 |
| 2 |
∴cos
| 3 |
| 2 |
| 1 |
| 10 |
| 7 |
| 4 |
故答案为:cos
| 3 |
| 2 |
| 1 |
| 10 |
| 7 |
| 4 |
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