题目内容
已知△ABC中,∠A=30°,a=1,则
=______.
| a-2b+c |
| sinA-2sinB+sinC |
∵由正弦定理,得
=
=
∴
=
=
,可得
=
∵△ABC中,∠A=30°,a=1,
∴
=
=2,可得
=2
故答案为:2
| a |
| sinA |
| b |
| sinB |
| c |
| sinC |
∴
| a |
| sinA |
| -2b |
| -2sinB |
| c |
| sinC |
| a-2b+c |
| sinA-2sinB+sinC |
| a |
| sinA |
∵△ABC中,∠A=30°,a=1,
∴
| a |
| sinA |
| 1 |
| sin30° |
| a-2b+c |
| sinA-2sinB+sinC |
故答案为:2
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