题目内容
已知sinθ+cosθ=
,θ∈(
,π).
(1)求tanθ的值;
(2)求sin(
-θ)•sin(
+θ)的值.
| 1 |
| 5 |
| π |
| 2 |
(1)求tanθ的值;
(2)求sin(
| π |
| 4 |
| π |
| 4 |
∵sinθ+cosθ=
两边平方可得sinθcosθ=-
∵θ∈(
,π)
∴sinθ=
,cosθ=-
(1)tanθ=
=-
(2)sin(
-θ)•sin(
+θ)=
(cosθ-sinθ)•
(sinθ+cosθ)
=
(cos2θ-sin2θ)=
(
-
)=-
| 1 |
| 5 |
两边平方可得sinθcosθ=-
| 12 |
| 25 |
∵θ∈(
| π |
| 2 |
∴sinθ=
| 4 |
| 5 |
| 3 |
| 5 |
(1)tanθ=
| sinθ |
| cosθ |
| 4 |
| 3 |
(2)sin(
| π |
| 4 |
| π |
| 4 |
| ||
| 2 |
| ||
| 2 |
=
| 1 |
| 2 |
| 1 |
| 2 |
| 9 |
| 25 |
| 16 |
| 25 |
| 7 |
| 50 |
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