题目内容
已知cos(15°+α)=
,α为第一象限角,求cos(75°-α)+sin(α+105°)的值.
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由cos(15°+α)=
,α为第一象限角,
可得sin(15°+α)=
,
cos(75°-α)+sin(α+105°)
=sin[90°-(75°-α)]+sin[90°+(15°+α)]
=sin(15°+α)+cos(15°+α)
=
+
=
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| 3 |
可得sin(15°+α)=
2
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cos(75°-α)+sin(α+105°)
=sin[90°-(75°-α)]+sin[90°+(15°+α)]
=sin(15°+α)+cos(15°+α)
=
2
| ||
| 3 |
| 1 |
| 3 |
=
2
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| 3 |
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