题目内容

18.已知两曲线的参数方程分别是$\left\{\begin{array}{l}{x=\sqrt{5}cosθ}\\{y=sinθ}\end{array}\right.$(0≤θ≤π)和$\left\{\begin{array}{l}{x=\frac{5}{4}t}\\{y=t}\end{array}\right.$(t∈R)求它们的交点坐标.

分析 把参数方程化为普通方程,联立方程组求两条曲线的交点的坐标.

解答 解:两曲线的参数方程分别是$\left\{\begin{array}{l}{x=\sqrt{5}cosθ}\\{y=sinθ}\end{array}\right.$(0≤θ≤π)和$\left\{\begin{array}{l}{x=\frac{5}{4}t}\\{y=t}\end{array}\right.$(t∈R),
则它们的普通方程分别为$\frac{{x}^{2}}{5}$+y2=1(y≥0)和y=$\frac{4}{5}$x,
由$\left\{\begin{array}{l}{\frac{{x}^{2}}{5}{+y}^{2}=1(y≥0)}\\{y=\frac{4}{5}x}\end{array}\right.$,求得$\left\{\begin{array}{l}{x=\frac{5}{6}}\\{y=\frac{2}{3}}\end{array}\right.$,故它们的交点坐标为($\frac{5}{6}$,$\frac{2}{3}$).

点评 本题主要考查把参数方程化为普通方程的方法,求两条曲线的交点的坐标,属于基础题.

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