题目内容
圆心在抛物线y=A.x2+y2-2x-y+
=0 B.x2+y2+2x-y+1=0
C.x2+y2+2x-y+
=0 D.x2+y2-2x+y+1=0
解析:设圆心C(a,b),则b=
a2,b+
=-a,解得a=-1,b=
,故圆的方程为(x+1)2+(y-
)2=1,
即x2+2x+y2-y+
=0.
答案:C
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