题目内容
计算12-22+32-42+…+992-1002=( )
| A.-100 | B.-200 | C.-1024 | D.-5050 |
∵12-22+32-42+…+992-1002
=(12-22)+(32-42)+…+(992-1002)
=(1+2)(1-2)+(3+4)(3-4)+…+(99+100)(99-100)
=-(1+2+3+…+99+100)
=-
=-5050.
故选D.
=(12-22)+(32-42)+…+(992-1002)
=(1+2)(1-2)+(3+4)(3-4)+…+(99+100)(99-100)
=-(1+2+3+…+99+100)
=-
| (1+100)×100 |
| 2 |
=-5050.
故选D.
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