题目内容

已知S是△ABC所在平面外一点,D是SC的中点,若
BD
=x
AB
+y
AC
+z
AS
,则x+y+z=______.
如图,D是SC的中点,故有
BD
=
1
2
(
BS
+
BC
)

=
1
2
(
BA
+
AS
)+
1
2
(
AC
-
AB
)

=-
AB
+
1
2
AC
+
1
2
AS

又由已知
BD
=x
AB
+y
AC
+z
AS

故x=-1,y=
1
2
,z=
1
2

代入得x+y+z=0
故答案为 0
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