ÌâÄ¿ÄÚÈÝ

1£®ÓÐһƿ»ìÓнÍĸ¾úµÄÆÏÌÑÌÇÅàÑøÒº£¬µ±Í¨È벻ͬŨ¶ÈµÄO2ʱ£¬Æä²úÉúµÄ¾Æ¾«ºÍCO2µÄÁ¿ÈçͼËùʾ£®¾ÝͼÖÐÐÅÏ¢ÍÆ¶Ï´íÎóµÄÊÇ£¨¡¡¡¡£©
A£®ÑõŨ¶ÈΪaʱ½Íĸ¾úûÓÐÓÐÑõºôÎü£¬Ö»½øÐÐÎÞÑõºôÎü
B£®µ±ÑõŨ¶ÈΪbºÍdʱ£¬½Íĸ¾úϸ°ûºôÎüµÄ¹ý³Ì»á²»Í¬
C£®µ±ÑõŨ¶ÈΪcʱ£¬$\frac{2}{5}$µÄÆÏÌÑÌÇÓÃÓÚ½Íĸ¾ú¾Æ¾«·¢½Í
D£®a¡¢b¡¢c¡¢d²»Í¬ÑõŨ¶ÈÏ£¬Ï¸°û¶¼²úÉúCO2ºÍATP

·ÖÎö ½â´ð±¾ÌâÊ×ÏÈÒªÊìÁ·ÕÆÎÕÓÐÑõºôÎüºÍÎÞÑõºôÎüµÄ»¯Ñ§·´Ó¦·½³Ìʽ£®
ÎÞÑõºôÎü£º¾Æ¾«·¢½Í£ºC6H12O6$\stackrel{ø}{¡ú}$2C2H5OH+2CO2+ÄÜÁ¿£»
ÓÐÑõºôÎü£ºC6H12O6+6O2+6 H2O$\stackrel{ø}{¡ú}$6CO2+12H2O+ÄÜÁ¿£®
²úÎïÖÐÈç¹ûÓÐC02²úÉú£¬ÔòÓÐÁ½ÖÖ¿ÉÄÜ£ºÓÐÑõºôÎü»ò¾Æ¾«·¢½Í£®
ÓÐÑõºôÎü¹ý³ÌÖУº·Ö½âÆÏÌÑÌÇ£º²úÉúµÄ¶þÑõ»¯Ì¼=1£º6£»
ÎÞÑõºôÎü¹ý³Ì£º·Ö½âÆÏÌÑÌÇ£º²úÉúµÄ¶þÑõ»¯Ì¼£º¾Æ¾«=1£º2£º2£®

½â´ð ½â£ºA¡¢·ÖÎöÇúÏß¿ÉÖªÑõÆøÅ¨¶ÈΪaʱ£¬²úÉú¾Æ¾«µÄÁ¿ÓëÊͷŶþÑõ»¯Ì¼µÄÁ¿ÏàµÈ£¬ËµÃ÷½Íĸ¾úÖ»½øÐÐÎÞÑõºôÎü£¬²»½øÐÐÓÐÑõºôÎü£¬AÕýÈ·£»
B¡¢·ÖÎöÇúÏß¿ÉÖªÑõÆøÅ¨¶ÈΪbʱ£¬²úÉú¶þÑõ»¯Ì¼µÄÁ¿¶àÓÚ²úÉúµÄ¾Æ¾«Á¿£¬´Ëʱ½Íĸ¾ú¼È½øÐÐÓÐÑõºôÎü£¬Ò²½øÐÐÎÞÑõºôÎü£¬ÑõÆøÅ¨¶ÈΪdʱ£¬²»²úÉú¾Æ¾«£¬ËµÃ÷¸ÃµãÖ»½øÐÐÓÐÑõºôÎü²»½øÐÐÎÞÑõºôÎü£¬BÕýÈ·£»
C¡¢µ±ÑõŨ¶ÈΪcʱ£¬¾Æ¾«µÄ²úÉúÁ¿Îª6£¬ËµÃ÷ÎÞÑõºôÎü¶þÑõ»¯Ì¼µÄ²úÉúÁ¿Îª6£¬ÔòÓÐÑõºôÎü¶þÑõ»¯Ì¼µÄ²úÉúÁ¿Îª15-6=9£¬¸ù¾ÝÓÐÑõºôÎüºÍÎÞÑõºôÎüµÄ»¯Ñ§·´Ó¦Ê½¿ÉÒÔ¼ÆË㣬ÓÐÑõºôÎüºÍÎÞÑõºôÎüÏûºÄµÄÆÏÌÑÌÇ·Ö±ðΪ1.5¡¢3£¬Òò´Ë$\frac{2}{3}$µÄÆÏÌÑÌÇÓÃÓÚ½Íĸ¾ú¾Æ¾«·¢½Í£¬C´íÎó£»
D¡¢a¡¢b¡¢c¡¢d²»Í¬ÑõŨ¶ÈÏ£¬Ï¸°û¶¼²úÉú[H]ºÍATP£¬DÕýÈ·£®
¹ÊÑ¡£ºC£®

µãÆÀ ±¾Ì⿼²éÁËϸ°ûºôÎüµÄÓйØÖªÊ¶£¬ÒªÇó¿¼ÉúÄܹ»Ê¶¼Ç½Íĸ¾úÓÐÑõºôÎüºÍÎÞÑõºôÎüµÄ·´Ó¦Ê½£¬ÕÆÎÕÆäÖÐÆÏÌÑÌÇ¡¢¶þÑõ»¯Ì¼¡¢¾Æ¾«Á¿µÄ±ÈÀý¹ØÏµ£¬ÔÙ½áºÏÇúÏßÐÅÏ¢Åжϸ÷µãµÄºôÎü·½Ê½£¬²¢½áºÏ·´Ó¦Ê½½øÐÐÏà¹Ø¼ÆË㣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø