ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿½üÄêÀ´£¬Ëæ×žÛõ¥¹¤ÒµµÄ¿ìËÙ·¢Õ¹£¬ÂÈÆøµÄÐèÇóÁ¿ºÍÂÈ»¯ÇâµÄ²ú³öÁ¿Ò²ËæÖ®Ñ¸ËÙÔö³¤¡£Òò´Ë£¬½«ÂÈ»¯Çâת»¯ÎªÂÈÆøµÄ¼¼Êõ³ÉΪ¿ÆÑ§Ñо¿µÄÈȵ㡣Çë»Ø´ð£º
(1)Èçͼ±íʾÔÚCuO´æÔÚÏÂHCl´ß»¯Ñõ»¯µÄ·´Ó¦¹ý³Ì£¬Ôò×Ü·´Ó¦µÄ»¯Ñ§·½³ÌΪ______¡£
![]()
(2)Ñо¿HCl´ß»¯Ñõ»¯·´Ó¦ÖÐζȡ¢
ºÍ
µÈÒòËØ¶ÔHClת»¯ÂʵÄÓ°Ï죬µÃµ½ÈçÏÂʵÑé½á¹û£º
¢ÙÀûÓÃNa2S2O3ÈÜÒººÍKIÈÜÒº²â¶¨·´Ó¦Éú³ÉCl2µÄÎïÖʵÄÁ¿£¬ÈôÏûºÄV1mLc1mol¡¤L-1µÄNa2S2O3ÈÜÒº£¬ÔòÉú³ÉCl2____________mol(ÒÑÖª2S2O
+I2=S4O
+2I-)¡£
¢Ú
±íʾ´ß»¯¼ÁµÄÖÊÁ¿ÓëHCl(g)Á÷ËÙÖ®±È£¬ÊǺâÁ¿·´Ó¦ÆøÌåÓë´ß»¯¼Á½Ó´¥Çé¿öµÄÎïÀíÁ¿¡£µ±
=4¡¢
=50g¡¤min¡¤mol-1ʱ£¬Ã¿·ÖÖÓÁ÷¾1g´ß»¯¼ÁµÄÆøÌåÌå»ýΪ_____L(ÕÛËãΪ±ê×¼×´¿öÏÂ)¡£
![]()
¢ÛÔÚ420¡æ¡¢
=3¡¢
=200g¡¤min¡¤mol-1Ìõ¼þÏ£¬¦Á(HCl)Ϊ33.3%£¬ÔòO2µÄ·´Ó¦ËÙÂÊΪ_______mol¡¤g-1¡¤min-1¡£
¢Ü±È½ÏÔÚÏÂÁÐÁ½ÖÖ·´Ó¦Ìõ¼þÏÂO2µÄ·´Ó¦ËÙÂÊ£ºv¢ñ_______v¢ò(Ìî¡°£¾¡±¡°=¡±»ò¡°£¼¡±)¡£
¢ñ.410¡æ¡¢
=3¡¢
=350g¡¤min¡¤mol-1£»
¢ò.390¡æ¡¢
=4¡¢
=350g¡¤min¡¤mol-1¡£
(3)ÔÚ101.325kPaʱ£¬ÒÔº¬N2µÄHClºÍO2µÄ»ìºÏÆøÌå²â¶¨²»Í¬Î¶ÈÏÂHCl´ß»¯Ñõ»¯·´Ó¦ÖÐHClµÄƽºâת»¯ÂÊ£¬µÃµ½Èçͼ½á¹û
![]()
¢Ù360¡æÊ±·´Ó¦µÄƽºâ³£ÊýK360Óë400¡æÊ±·´Ó¦µÄƽºâ³£ÊýK400Ö®¼äµÄ¹ØÏµÊÇK360_________K400¡£(Ìî¡°£¾¡±¡°=¡±»ò¡°£¼¡±)¡£
¢ÚÒ»¶¨Î¶ÈÏÂËæ×Å
µÄÔö´ó£¬HClµÄƽºâת»¯ÂÊ_______(Ìî¡°Ôö´ó¡±¡°¼õС¡±»ò¡°²»±ä¡±)£¬ÔÒòΪ___________________¡£
¡¾´ð°¸¡¿2HCl(g)+
O2(g)=H2O(g)+Cl2(g) H=H1+H2+H3
c1V1¡Á10-3 0.56
£¾ £¾ ¼õС Ëæ×Å
Ôö´ó£¬N2º¬Á¿Ôö´ó£¬HCl(g)¡¢O2(g)¡¢H2O(g)ºÍCl2(g)µÄŨ¶È¾ùʹ·´Ó¦ÌåϵµÄŨ¶ÈÉÌQ£¾K£¬Æ½ºâÄæÏòÒÆ¶¯£¬¦Á(HCl)¼õС
¡¾½âÎö¡¿
(1)¸ù¾Ý¸Ç˹¶¨ÂɼÆËã×Ü·´Ó¦ìʱ䣻
(2)¸ù¾Ý
µÄµ¥Î»¿ÉÖªHClµÄÁ÷ËÙÊÇÖ¸µ¥Î»Ê±¼äÄÚÆøÁ÷ÖÐHClµÄÎïÖʵÄÁ¿£¬ËùÒÔ
µÄµ¹Êý¼´1minÁ÷¾1g´ß»¯¼ÁµÄHClµÄÎïÖʵÄÁ¿£¬¾Ý´Ë·ÖÎö×÷´ð£»
(3)¾Ýͼ¿ÉÖªµ±
Ò»¶¨Ê±£¬Î¶ÈÔ½¸ßHClµÄת»¯ÂÊԽС£¬ËùÒÔÕý·´Ó¦Îª·ÅÈÈ·´Ó¦£»
Ôö´ó£¬Ò²¾ÍÊǵ¥Î»Ê±¼äÄÚͨ¹ýµ¥Î»ÖÊÁ¿µÄ´ß»¯¼ÁµÄHClºÍO2µÄÁ¿¼õÉÙ¡£
(1)¸ù¾Ý¸Ç˹¶¨ÂÉ£¬²»¹Ü»¯Ñ§·´Ó¦ÊÇÒ»²½Íê³É»¹ÊÇ·Ö¼¸²½Íê³É£¬Æä·´Ó¦Èȶ¼ÊÇÏàͬµÄ£¬ÓÉͼ1¿ÉÖªÈÈ»¯Ñ§·½³ÌʽΪ2HCl(g)+
O2(g)=H2O(g)+Cl2(g)H=H1+H2+H3£»
(2)¢Ù¸ù¾ÝÌâÖÐÀë×Ó·½³Ìʽ2S2O32-+I2=S4O
+2l¡¥£¬Cl2Ñõ»¯I¡¥µÄÀë×Ó·½³ÌʽΪCl2+2I¡¥=2Cl¡¥+I2£¬¿ÉÒԵõ½ÈçϹØÏµÊ½£º2S2O32-¡«I2¡«Cl2£¬n(Cl2)=
n(S2O32-)=
c1V1¡Á10-3mol£»
¢Úµ±
=50g¡¤min¡¤mol-1ʱ£¬Ã¿·ÖÖÓÁ÷¾1g´ß»¯¼ÁµÄHClΪ
mol£¬
=4£¬ËùÒÔÿ·ÖÖÓÁ÷¾1g´ß»¯¼ÁµÄO2Ϊ
mol£¬×ÜÆøÌåµÄÎïÖʵÄÁ¿Îª
£¬Ìå»ýΪ
=0.56L£»
¢Û
=200g¡¤min¡¤mol-1ʱ¦Á(HCl)Ϊ33.3%£¬Ôòv(HCl)=
¡Á33.3%molg-1min-1£¬¸ù¾Ý»¯Ñ§·½³ÌʽHClºÍO2·´Ó¦µÄ±ÈÀýΪ4£º1£¬v(O2)=
v(HCl)=
¡Á
¡Á33.3%molg-1min-1=
molg-1min-1£»
¢Ü¸ù¾ÝµÚ¢ÛÌâµÄ¼ÆËã¹ý³Ì¿ÉÖª£¬µ±
Ïàͬʱ£¬HClµÄת»¯ÂÊÔ½´ó£¬·´Ó¦ËÙÂÊÔ½´ó£¬¾Ýͼ¿ÉÖª410¡æ¡¢
=3µÄÇé¿öÏÂHClµÄת»¯Âʽϴó£¬ËùÒÔvI£¾v¢ò£»
(3)¢ÙÓÉͼ¿ÉÖª£¬µ±
Ïàͬʱ£¬Î¶ÈÔ½¸ßHClƽºâת»¯ÂÊԽС£¬ËµÃ÷¸Ã·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬Éý¸ßζȣ¬Æ½ºâÄæÏòÒÆ¶¯£¬KÖµ¼õС£¬ÔòK360£¾K400£»
¢ÚÒ»¶¨Î¶ÈÏÂËæ×Å
Ôö´ó£¬Í¨¹ý´ß»¯¼ÁµÄ»ìºÏÆøÌåÖÐHClºÍO2Á¿±äС£¬N2µÄÁ¿±ä´ó£¬Ï൱ÓÚ·´Ó¦ÎïºÍÉú³ÉÎïµÄŨ¶Èͬʱ±äСÏàͬ±¶Êý£¬¸ù¾ÝŨ¶ÈÉÌQc=
£¬Èô¸÷ÎïÖÊŨ¶È±äСÏàͬ±¶Êýʱ£¬»áʹQc´óÓÚK£¬´ËʱƽºâÄæÏòÒÆ¶¯£¬HClµÄƽºâת»¯ÂʼõС¡£
¡¾ÌâÄ¿¡¿¶ÔÓÚ¿ÉÄæ·´Ó¦N2£¨g£©+3H2£¨g£©
2NH3£¨g£©¦¤H£¼0£¬ÏÂÁÐÑо¿Ä¿µÄºÍʾÒâͼÏà·ûµÄÊÇ
A | B | C | D | |
Ñо¿Ä¿µÄ | ѹǿ¶Ô·´Ó¦µÄÓ°ÏìP2£¾P1 | ζȶԷ´Ó¦µÄÓ°Ïì | ƽºâÌåϵÔö¼ÓµªÆø¶Ô·´Ó¦µÄÓ°Ïì | ´ß»¯¼Á¶Ô·´Ó¦µÄÓ°Ïì |
ͼʾ |
|
|
|
|
A. AB. BC. CD. D
¡¾ÌâÄ¿¡¿Ä³ÓлúÎïµÄ½á¹¹¼òʽÈçÏ£º
![]()
£¨1£©¸ÃÎïÖʱ½»·ÉÏÒ»ÂÈ´úÎïÓÐ____________________ÖÖ£»
£¨2£©1 mol¸ÃÎïÖʺÍäåË®»ìºÏ£¬ÏûºÄBr2µÄÎïÖʵÄÁ¿Îª____________________mol£»
£¨3£©1 mol¸ÃÎïÖʺÍH2¼Ó³É×î¶àÐèH2____________________mol£»
£¨4£©ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ____________________¡£
A£®´ËÎïÖʿɷ¢Éú¼Ó³É¡¢È¡´ú¡¢Ñõ»¯µÈ·´Ó¦ |
B£®¸ÃÎïÖÊÒ×ÈÜÓÚË® |
C£®¸ÃÎïÖÊÄÜʹäåË®ÍÊÉ« |
D£®¸ÃÎïÖÊÄÜʹËáÐÔKMnO4ÈÜÒºÍÊÉ« |
E.·Ö×ÓʽÊÇC15H18