ÌâÄ¿ÄÚÈÝ

9£®ÒÑÖª£º³£ÎÂÏÂŨ¶ÈΪ0.1mol/LµÄÏÂÁÐÈÜÒºµÄpHÈç±í£º
ÈÜÖÊNaFNa2CO3NaClONaHCO3
pH7.511.69.78.3
ÏÂÁÐÓйØËµ·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®ÔÚÏàͬζÈÏ£¬Í¬Å¨¶ÈµÄÈýÖÖËáÈÜÒºµÄµ¼µçÄÜÁ¦Ë³Ðò£ºH2CO3£¼HClO£¼HF
B£®Èô½«CO2ͨÈë0.1mol/L Na2CO3ÈÜÒºÖÁÈÜÒºÖÐÐÔ£¬ÔòÈÜÒºÖУº2c£¨CO32-£©+c£¨HCO3-£©=0.1mol/L
C£®µÈÌå»ýµÈÎïÖʵÄÁ¿Å¨¶ÈµÄNaClOÈÜÒºÓëNaFÈÜÒºÖÐÀë×Ó×ÜÊý´óС£ºNǰ£¼Nºó
D£®ÏòNa2CO3ÈÜÒºÖÐͨÈëÉÙÁ¿µÄHFÆøÌ壬»¯Ñ§·´Ó¦·½³ÌʽΪ£ºNa2CO3+2HF¨TCO2+H2O+2NaF

·ÖÎö A£®ÈÜÒºpHÔ½´ó£¬¶ÔÓ¦ËáµÄËáÐÔÔ½Èõ£¬Å¨¶ÈÏàµÈʱÆäÈÜÒºµÄµ¼µçÐÔԽǿ£»
B£®ÈÜҺΪÖÐÐÔʱ£ºc£¨H+£©=c£¨OH-£©£¬¸ù¾ÝµçºÉÊØºã¿ÉÖª£º2c£¨CO32-£©+c£¨HCO3-£©=c£¨Na+£©£»
C£®¸ù¾ÝËáÐÔÅжÏË®½â³Ì¶È£¬È»ºó½áºÏµçºÉÊØºãÅжÏÁ½ÈÜÒºÖк¬ÓÐÒõÀë×ÓÊýÄ¿´óС£»
D£®HFÉÙÁ¿£¬·´Ó¦Éú³ÉµÄÊÇNaHCO3£®

½â´ð ½â£ºA£®ÈÜÒºpHÔ½´ó£¬¶ÔÓ¦ËáµÄËáÐÔÔ½Èõ£¬¸ù¾Ý±íÖÐÊý¾Ý¿ÉÖª£¬ËáÐÔ´óСΪ£ºHF£¾H2CO3£¾HClO£¾HCO3-£¬Î¶ȡ¢Å¨¶ÈÏàͬʱ£¬ËáÐÔԽǿ£¬ÈÜÒºµ¼µçÄÜÁ¦Ô½Ç¿£¬ÔòÈýÖÖÈÜÒºµ¼µçÐÔ´óСΪ£ºHClO£¼H2CO3£¼HF£¬¹ÊA´íÎó£»
B£®Èô½«CO2ͨÈë0.1mol/L Na2CO3ÈÜÒºÖÁÈÜÒºÖÐÐÔ£¬Ôòc£¨H+£©=c£¨OH-£©£¬¸ù¾ÝµçºÉÊØºã¿ÉÖª£º2c£¨CO32-£©+c£¨HCO3-£©=c£¨Na+£©=0.2mol/L£¬¹ÊB´íÎó£»
C£®NaClO¡¢NaFÈÜÒºÖдÎÂÈËá¸ùÀë×Ó¡¢·úÀë×Ó·¢ÉúË®½âʹÈÜÒº³Ê¼îÐÔ£¬ÇâÀë×ÓŨ¶ÈСÓÚ10-7mol/L£¬ÓÉÓÚËáÐÔHF£¾HClO£¬Ôò´ÎÂÈËá¸ùµÄË®½â³Ì¶È´óÓÚ·úÀë×Ó£¬¹Ê´ÎÂÈËáÄÆÈÜÒºÖÐÇâÑõ¸ùÀë×ÓŨ¶È´óÓÚ·ú»¯ÄÆ£¬´ÎÂÈËáÄÆÈÜÒºÖеÄÇâÀë×ÓŨ¶ÈСÓÚ·ú»¯ÄÆ£»Á½ÈÜÒºÖÐÄÆÀë×ÓŨ¶ÈÏàµÈ£¬Á½ÈÜÒºÖÐÒõÀë×ÓŨ¶È=c£¨Na+£©+c£¨H+£©£¬ÓÉÓÚÈÜÒºÌå»ýÏàµÈ£¬Ôò´ÎÂÈËáÄÆÈÜÒºÖÐÒõÀë×ÓÊýĿСÓÚ·ú»¯ÄÆ£¬¼´£ºNǰ£¼Nºó£¬¹ÊCÕýÈ·£»
D£®ÏòNa2CO3ÈÜÒºÖÐͨÈëÉÙÁ¿µÄHFÆøÌ壬·´Ó¦Éú³É̼ËáÇâÄÆºÍ·ú»¯ÄÆ£¬ÕýÈ·µÄ»¯Ñ§·´Ó¦·½³ÌʽΪ£ºNa2CO3+HF¨TNaHCO3+NaF£¬¹ÊD´íÎó£»
¹ÊÑ¡C£®

µãÆÀ ±¾Ì⿼²éÁËÀë×ÓŨ¶È´óС±È½Ï£¬ÌâÄ¿ÄѶÈÖеȣ¬ÕýÈ·ÅжÏÈÜÒºËáÐÔÇ¿ÈõΪ½â´ð¹Ø¼ü£¬×¢ÒâÕÆÎÕµçºÉÊØºã¡¢ÎïÁÏÊØºã¼°ÑεÄË®½âÔ­ÀíµÄº¬Òå¼°Ó¦Ó÷½·¨£¬ÊÔÌâÅàÑøÁËѧÉúµÄ·ÖÎöÄÜÁ¦¼°Áé»îÓ¦ÓÃÄÜÁ¦£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø