ÌâÄ¿ÄÚÈÝ
ij¿ÎÍâÐËȤС×éÓû²â¶¨Ä³NaOHÈÜÒºµÄŨ¶È,Æä²Ù×÷²½ÖèÈçÏÂ:
¢Ù ½«¼îʽµÎ¶¨¹ÜÓÃÕôÁóˮϴ¾»ºó,Óôý²âÈÜÒºÈóÏ´ºó,ÔÙ×¢Èë´ý²âÈÜÒº,µ÷½ÚµÎ¶¨¹ÜµÄ¼â×첿·Ö³äÂúÈÜÒº,²¢Ê¹ÒºÃæ´¦ÓÚ"0"¿Ì¶ÈÒÔϵÄλÖÃ,¼Ç϶ÁÊý£»½«×¶ÐÎÆ¿ÓÃÕôÁóˮϴ¾»ºó,Óôý²âÈÜÒºÈóÏ´×¶ÐÎÆ¿2¡«3´Î£»´Ó¼îʽµÎ¶¨¹ÜÖзÅÈë25£®00mL´ý²âÈÜÒºµ½×¶ÐÎÆ¿ÖУ»
¢Ú ½«ËáʽµÎ¶¨¹ÜÓÃÕôÁóˮϴ¾»ºó,Á¢¼´ÏòÆäÖÐ×¢Èë0£®1000mol/L±ê×¼ÑÎËá,µ÷½ÚµÎ¶¨¹ÜµÄ¼â×첿·Ö³äÂúÈÜÒº,²¢Ê¹ÒºÃæ´¦ÓÚ"0"¿Ì¶ÈÒÔϵÄλÖÃ,¼Ç϶ÁÊý£»
¢Û Ïò×¶ÐÎÆ¿ÖеÎÈë·Ó̪×÷ָʾ¼Á,½øÐеζ¨.µÎ¶¨ÖÁÖÕµã,²âµÃËùºÄÑÎËáµÄÌå»ýΪV1mL£»
¢Ü ÖØ¸´ÒÔÉϹý³Ì,µ«Ôڵζ¨¹ý³ÌÖÐÏò×¶ÐÎÆ¿¼ÓÈë5mLµÄÕôÁóË®,²âµÃËùºÄÑÎËáµÄÌå»ýΪV2mL¡£
¢Ù ½«¼îʽµÎ¶¨¹ÜÓÃÕôÁóˮϴ¾»ºó,Óôý²âÈÜÒºÈóÏ´ºó,ÔÙ×¢Èë´ý²âÈÜÒº,µ÷½ÚµÎ¶¨¹ÜµÄ¼â×첿·Ö³äÂúÈÜÒº,²¢Ê¹ÒºÃæ´¦ÓÚ"0"¿Ì¶ÈÒÔϵÄλÖÃ,¼Ç϶ÁÊý£»½«×¶ÐÎÆ¿ÓÃÕôÁóˮϴ¾»ºó,Óôý²âÈÜÒºÈóÏ´×¶ÐÎÆ¿2¡«3´Î£»´Ó¼îʽµÎ¶¨¹ÜÖзÅÈë25£®00mL´ý²âÈÜÒºµ½×¶ÐÎÆ¿ÖУ»
¢Ú ½«ËáʽµÎ¶¨¹ÜÓÃÕôÁóˮϴ¾»ºó,Á¢¼´ÏòÆäÖÐ×¢Èë0£®1000mol/L±ê×¼ÑÎËá,µ÷½ÚµÎ¶¨¹ÜµÄ¼â×첿·Ö³äÂúÈÜÒº,²¢Ê¹ÒºÃæ´¦ÓÚ"0"¿Ì¶ÈÒÔϵÄλÖÃ,¼Ç϶ÁÊý£»
¢Û Ïò×¶ÐÎÆ¿ÖеÎÈë·Ó̪×÷ָʾ¼Á,½øÐеζ¨.µÎ¶¨ÖÁÖÕµã,²âµÃËùºÄÑÎËáµÄÌå»ýΪV1mL£»
¢Ü ÖØ¸´ÒÔÉϹý³Ì,µ«Ôڵζ¨¹ý³ÌÖÐÏò×¶ÐÎÆ¿¼ÓÈë5mLµÄÕôÁóË®,²âµÃËùºÄÑÎËáµÄÌå»ýΪV2mL¡£
ÊԻشðÏÂÁÐÎÊÌâ:
£¨1£©µÎ¶¨ÖÕµãʱµÄÏÖÏóΪ׶ÐÎÆ¿ÖеÄÈÜÒºÓÉ____________________£»
£¨2£©µÎ¶¨Ê±±ßµÎ±ßÒ¡¶¯×¶ÐÎÆ¿,ÑÛ¾¦Ó¦¹Û²ì_________________£»
£¨3£©¸ÃС×éÔÚ²½Öè¢ÙÖеĴíÎóÊÇ______________£¬ÓÉ´ËÔì³ÉµÄ²â¶¨½á¹û_________(ÌîÆ«¸ß¡¢Æ«µÍ»òÎÞÓ°Ïì)£»
£¨4£©²½Öè¢ÚȱÉٵIJÙ×÷ÊÇ______________________£»
£¨5£©ÏÂͼ,ÊÇij´ÎµÎ¶¨Ê±µÄµÎ¶¨¹ÜÖеÄÒºÃæ,Æä¶ÁÊýΪ___________mL£»
£¨1£©µÎ¶¨ÖÕµãʱµÄÏÖÏóΪ׶ÐÎÆ¿ÖеÄÈÜÒºÓÉ____________________£»
£¨2£©µÎ¶¨Ê±±ßµÎ±ßÒ¡¶¯×¶ÐÎÆ¿,ÑÛ¾¦Ó¦¹Û²ì_________________£»
£¨3£©¸ÃС×éÔÚ²½Öè¢ÙÖеĴíÎóÊÇ______________£¬ÓÉ´ËÔì³ÉµÄ²â¶¨½á¹û_________(ÌîÆ«¸ß¡¢Æ«µÍ»òÎÞÓ°Ïì)£»
£¨4£©²½Öè¢ÚȱÉٵIJÙ×÷ÊÇ______________________£»
£¨5£©ÏÂͼ,ÊÇij´ÎµÎ¶¨Ê±µÄµÎ¶¨¹ÜÖеÄÒºÃæ,Æä¶ÁÊýΪ___________mL£»
£¨6£©¸ù¾ÝÏÂÁÐÊý¾Ý:
Çë¼ÆËã´ý²âÉÕ¼îÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È.(Çëд³ö½â´ð¹ý³Ì) ___________________________________________
£¨1£©·ÛºìÉ«±äΪÎÞÉ«ÇÒÔÚ°ë·ÖÖÓÄÚ²»»Ö¸´(·Ûºìɫд³ÉºìɫҲ¸ø·Ö)
£¨2£©×¶ÐÎÆ¿ÄÚÈÜÒºÑÕÉ«µÄ±ä»¯
£¨3£©Óôý²âÒºÈóÏ´×¶ÐÎÆ¿£»Æ«¸ß
£¨4£©Óñê×¼ÒºÈóÏ´µÎ¶¨¹Ü2~3´Î
£¨5£©22£®60(»ò22£®59)
£¨6£©½â:Á½´ÎÏûºÄHClÈÜÒºÌå»ýµÄƽ¾ùֵΪ:20£®00mL.
c(NaOH)=(0£®1000mol/L¡Á20£®00¡Á10-3L)/(25£®00¡Á10-3L) =0£®0800mol/L
£¨2£©×¶ÐÎÆ¿ÄÚÈÜÒºÑÕÉ«µÄ±ä»¯
£¨3£©Óôý²âÒºÈóÏ´×¶ÐÎÆ¿£»Æ«¸ß
£¨4£©Óñê×¼ÒºÈóÏ´µÎ¶¨¹Ü2~3´Î
£¨5£©22£®60(»ò22£®59)
£¨6£©½â:Á½´ÎÏûºÄHClÈÜÒºÌå»ýµÄƽ¾ùֵΪ:20£®00mL.
c(NaOH)=(0£®1000mol/L¡Á20£®00¡Á10-3L)/(25£®00¡Á10-3L) =0£®0800mol/L
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿