Question

17£®0.5molCH₄ÍêȫȼÉÕÉú³ÉCO₂ºÍH₂O£¨l£©Ê±·Å³ö445kJÈÈÁ¿£¬ÔòÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÕýÈ·µÄÊÇ£¨¡¡¡¡£©

• A£® 2CH₄£¨g£©+4O₂£¨g£©¨T2CO₂£¨g£©+4H₂O£¨l£©¡÷H=+890kJ•mol^-1
• B£® CH₄£¨g£©+2O₂£¨g£©¨TCO₂£¨g£©+2H₂O£¨l£©¡÷H=+890kJ•mol^-1
• C£® CH₄£¨g£©+2O₂£¨g£©¨TCO₂£¨g£©+2H₂O£¨l£©¡÷H=890kJ•mol^-1
• D£® $\frac{1}{2}$ CH₄£¨g£©+O₂£¨g£©¨T$\frac{1}{2}$CO₂£¨g£©+H₂O£¨l£©¡÷H=-445kJ•mol^-1

Answer 1

·ÖÎö ¸ù¾ÝÈÈ»¯Ñ§·½³ÌʽµÄÊéд·½·¨¿ÉÖª£¬»¯Ñ§¼ÆÁ¿ÊýÓë·´Ó¦ÈȳÉÕý±È£¬²¢×¢Òâ±êÃ÷ÎïÖʵľۼ¯×´Ì¬À´½â´ð£®

½â´ð ½â£º0.5mol CH₄ÍêȫȼÉÕÉú³ÉCO₂ºÍҺ̬ˮʱ£¬·Å³ö445KJÈÈÁ¿£¬
1molCH₄ÔÚÑõÆøÖÐȼÉÕÉú³ÉCO₂ºÍҺ̬ˮ£¬·Å³ö890kJÈÈÁ¿£¬
ÔòÈÈ»¯Ñ§·½³ÌʽΪCH₄£¨g£©+2O₂£¨g£©¨TCO₂£¨g£©+2H₂O£¨l£©¡÷H=-890KJ/mol£¬»òÕß$\frac{1}{2}$ CH₄£¨g£©+O₂£¨g£©¨T$\frac{1}{2}$CO₂£¨g£©+H₂O£¨l£©¡÷H=-445kJ•mol^-1£¬×ÛÉÏËùÊöDÕýÈ·£¬¹ÊÑ¡D£®

µãÆÀ ±¾ÌâÖ÷Òª¿¼²éÁËÈÈ»¯Ñ§·½³ÌʽµÄÊéд£¬ÄѶȲ»´ó£¬¸ù¾Ý¿Î±¾ÖªÊ¶¼´¿ÉÍê³É£®