ÌâÄ¿ÄÚÈÝ

£¨11·Ö£©Ä³»¯Ñ§ÊµÑéС×éͬѧÀûÓÃÒÔÏÂ×°ÖÃÖÆ±¸°±Æø£¬²¢Ì½¾¿°±ÆøµÄÐÔÖÊ£¨²¿·ÖÒÇÆ÷ÒÑÂÔÈ¥£©¡£

Çë»Ø´ð£º
£¨1£©ÊµÑéÊÒÖÆ±¸°±ÆøµÄ»¯Ñ§·½³ÌʽΪ                    £»¸ÉÔï°±Æø³£ÓõĸÉÔï¼ÁÊÇ               ¡£
£¨2£©ÊÕ¼¯°±ÆøÊ±£¬ÇëÄãÑ¡Ôñ°±ÆøµÄ½øÆø¿Ú        £¨Ìî¡°a¡±»ò¡°b¡±£©£¬ÀíÓÉÊÇ                            ¡£
£¨3£©Èô¹Û²ìµ½×°ÖÃBÖеÄÉÕÆ¿ÄÚ²úÉúÁ˺ìÉ«ÅçȪ£¬Ôò˵Ã÷°±Æø¾ßÓеÄÐÔÖÊÊÇ                              ¡£
£¨4£©Îª·ÀÖ¹»·¾³ÎÛȾ£¬ÒÔÏÂ×°Öã¨Ê¢·ÅµÄÒºÌå¾ùΪˮ£©¿ÉÓÃÓÚÎüÊÕ¶àÓà°±ÆøµÄÊÇ             £¨                  ÌîÐòºÅ£©¡£

£¨5£©°±ÆøÔÚ´ß»¯¼Á²¢ÇÒ¼ÓÈÈʱ»á±»¿ÕÆøÑõ»¯£¬ÕâÊǹ¤ÒµÖÆÏõËáµÄµÚÒ»²½·´Ó¦£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ                      ¡£
£¨1£©2NH4Cl+Ca(OH)22NH3¡ü£«CaCl2+2H2O£»¼îʯ»Ò 
£¨2£©½øÆø¿Ú   a £¨Ìî¡°a¡±»ò¡°b¡±£©£¬ÒòΪ°±ÆøµÄÃÜ¶È±È¿ÕÆøÇᣬa¿Ú½øÊÇÏòÏÂÅÅÆø
£¨3£©¼«Ò×ÈÜÓÚË®£¬ÓëË®·´Ó¦Éú³É¼î         
£¨4£©¢Ú¢Ü¢Ý  
£¨5 4NH3+5O24NO+6H2O
£¨1£©ÊµÑéÊÒÖÆÈ¡°±Æø³£ÓÃÊìʯ»ÒºÍÂÈ»¯ï§¼ÓÈÈÖÆ±¸£¬°±ÆøÊôÓÚ¼îÐÔÆøÌ壬¿ÉÓüîʯ»ÒÀ´¸ÉÔï¡£
£¨2£©°±ÆøÃܶÈСÓÚ¿ÕÆøµÄ£¬ËùÒÔÊÕ¼¯°±ÆøÊ±Ó¦ÓÃÏòÏÂÅÅ¿ÕÆø·¨£¬¼´´Óa½ø¡£
£¨3£©²úÉúÅçȪ£¬ËµÃ÷ÉÕÆ¿ÄÚѹǿ˲¼ä½µµÍ£¬Òò´Ë°±Æø¼«Ò×ÈÜÓÚË®¡£ÈÜÒºÏÔºìÉ«£¬»¹ËµÃ÷°±ÆøºÍË®·´Ó¦ÓмîÉú³É¡£
£¨4£©°±Æø¼«Ò×ÈÜÓÚË®£¬Òò´ËÎüÊÕ°±ÆøÊ±Òª×¢Òâ·ÀÖ¹µ¹Îü¡£¢ÙÎüÊÕ²»ÍêÈ«£¬¢ÛÈÝÒ×µ¹Îü£¬ËùÒÔ´ð°¸ÊǢڢܢݡ£
£¨5£©¿¼²é°±µÄ´ß»¯Ñõ»¯£¬°±Æø·¢Éú´ß»¯Ñõ»¯Ê±Éú³ÉÒ»Ñõ»¯µªºÍË®¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø