ÌâÄ¿ÄÚÈÝ

ÔÚµÚÒ»´ÎÊÀ½ç´óÕ½ÆÚ¼ä£¬µÂ¹ú¾Í¿ªÊ¼ÖÆÔìÍé»ù±½»ù»ÇËáÑÎÒÔ´úÌæ·ÊÔí£®1930Ä꣬ÃÀ¹úNational Aniline¹«Ë¾Õýʽ½«Íé»ù±½»ÇËáÄÆ×÷ΪÁ®¼ÛµÄºÏ³ÉÏ´µÓ¼ÁÏúÊÛ£®ÕâÖÖ²úÆ·£¬ÔÚµÚ¶þ´ÎÊÀ½ç´óÕ½ºóµÄ1945¡«1950Äê¼äѸËÙÆÕ¼°£®ÔÚÈÕ±¾£¬ÀûÓÃÓ²ÐÔÐÍABS£¨´øÖ§Á´µÄÍé»ù±½»ÇËáÑΣ©µÄºÏ³ÉÏ´µÓ¼ÁµÄ²úÁ¿£¬ÔÚ1963ÄêÒѳ¬¹ý·ÊÔí£®µ«ÊÇËæ×źϳÉÏ´µÓ¼ÁÏû·ÑÁ¿µÄÔö¼Ó£¬ÒýÆðÁ˺Ӵ¨·¢ÉúÅÝÄ­µÈÎÛȾˮÖʵÄÎÊÌ⣮Òò¶ø¸ÄÓöÔ΢ÉúÎï½µ½âÐÔÁ¼ºÃµÄÈíÐÔÐÍLAS£¨Ö±Á´Íé»ù±½»ÇËáÑΣ©£®
£¨1£©ÈíÐÔÐÍLAS×î³£¼ûµÄÊÇÖ±Á´Ê®¶þÍé»ù±½»ÇËáÄÆ£º£¬Æä½á¹¹ÖÐÓë·ÊÔí£¨C17H35COONa£©µÄÔ÷Ë®»ùÍÅ-C17H35Ï൱µÄ»ùÍÅΪ
 
£¬
£¨2£©µ±Ï´µÓÓÃˮӲ¶È½Ï´óʱ£¬Ï´Ò·ÛÓë·ÊÔíÏà±È£¬
 
Ï´µÓЧ¹û½ÏºÃ£¬Ô­ÒòÊÇ·ÊÔí
 
£®
£¨3£©1999Äê1ÔÂ1ÈÕ¿ªÊ¼µÄÌ«ºþÁ÷Óò½ûÁ×Ðж¯ÊÇÖ¸
 
£¬Ö÷ҪĿµÄÊÇ
 
£®
£¨4£©ÏÖÔÚÊг¡ÉÏÏúÊ۵ļÓøϴÒ·ÛÖк¬ÓмîÐÔµ°°×ø£¬Ëü¶ÔÏ´µÓ
 
ÀàÎÛ×ÕЧ¹û¼«ºÃ£¬Ô­ÒòÊÇ
 
£®
¿¼µã£º·ÊÔí¡¢ºÏ³ÉÏ´µÓ¼Á
רÌ⣺Óлú»¯Ñ§»ù´¡
·ÖÎö£º£¨1£©Ô÷Ë®»ùÍÅΪÏà¶Ô·Ö×ÓÖÊÁ¿½Ï´óµÄÌþ»ù£»
£¨2£©·ÊÔíÒ×ÓëCa2+¡¢Mg2+Éú³É³Áµí£¬Ê§È¥È¥ÎÛÄÜÁ¦£»
£¨3£©Ì«ºþÁ÷Óò½ûÁ×Ðж¯ÊÇÖ¸ÔÚÌ«ºþÁ÷Óò½ûֹʹÓá¢ÏúÊÛº¬Á×Ï´Ò·ۣ»Á×ÔªËØÊÇÖ²ÎïÉú³¤µÄÓªÑøÔªËØ£¬Ë®ÌåÁ׺¬Á¿¹ý¸ß»áÒýÆðÔåÀà´óÁ¿·±Ö³£¬ÎÛȾºþË®£»
£¨4£©¼ÓøϴÒ·ÛÖк¬ÓмîÐÔµ°°×ø£¬ÄÜʹµ°°×ÖÊ·¢ÉúË®½â£®
½â´ð£º ½â£»£¨1£©Ô÷Ë®»ùÍÅΪÏà¶Ô·Ö×ÓÖÊÁ¿½Ï´óµÄÌþ»ù£¬ÔòµÄÔ÷Ë®»ùÍÅΪ£»
¹Ê´ð°¸Îª£º£»
£¨2£©Ë®Ó²¶È½Ï´óʱCa2+¡¢Mg2+Ũ¶È½Ï´ó£¬·ÊÔíµÄÖ÷Òª³É·ÖÊǸ߼¶Ö¬·¾ËáÄÆ£¬Ò×ÓëCa2+¡¢Mg2+Éú³É³Áµí£¬Ê§È¥È¥ÎÛÄÜÁ¦£¬ËùÒÔµ±Ï´µÓÓÃˮӲ¶È½Ï´óʱ£¬Ï´Ò·۵ÄÏ´µÓЧ¹û½ÏºÃ£»
¹Ê´ð°¸Îª£ºÏ´Ò·ۣ»·ÊÔíÒ×ÓëCa2+¡¢Mg2+Éú³É³Áµí£»
£¨3£©Ì«ºþÁ÷Óò½ûÁ×Ðж¯ÊÇÖ¸ÔÚÌ«ºþÁ÷Óò½ûֹʹÓá¢ÏúÊÛº¬Á×Ï´Ò·ۣ»Á×ÔªËØÊÇÖ²ÎïÉú³¤µÄÓªÑøÔªËØ£¬Ë®ÌåÁ׺¬Á¿¹ý¸ß»áÒýÆðÔåÀà´óÁ¿·±Ö³£¬ÎÛȾºþË®£» ËùÒÔ½ûÁ×Ðж¯µÄÄ¿µÄÊÇ·Àֹ̫ºþÁ÷ÓòË®ÌåÁ׺¬Á¿¹ý¸ß¶øÆðÔåÀà´óÁ¿·±Ö³£»
¹Ê´ð°¸Îª£ºÔÚÌ«ºþÁ÷Óò½ûֹʹÓá¢ÏúÊÛº¬Á×Ï´Ò·ۣ»·Àֹ̫ºþÁ÷ÓòË®ÌåÁ׺¬Á¿¹ý¸ß¶øÆðÔåÀà´óÁ¿·±Ö³£»
£¨4£©¼ÓøϴÒ·ÛÖк¬ÓмîÐÔµ°°×ø£¬ÄÜʹµ°°×ÖÊ·¢ÉúË®½â£¬ËùÒÔ¼ÓøϴÒ·۶ÔÏ´µÓѪ×Õ¡¢ÄÌ×յȺ¬Óе°°×ÖʵÄÎÛ×ÕЧ¹û¼«ºÃ£»
¹Ê´ð°¸Îª£ºÑª×Õ¡¢ÄÌ×Õ£»Ñª×Õ¡¢ÄÌ×ÕÖ÷Òª³É·ÖÊǵ°°×ÖÊ£¬ÄÜÔÚµ°°×ø´ß»¯ÏÂË®½â£®
µãÆÀ£º±¾Ì⿼²éÁ˺ϳÉÏ´µÓ¼Á£¬²àÖØÓÚ»¯Ñ§ÖªÊ¶ÔÚÉú²úÉú»îÖÐÓ¦ÓõĿ¼²é£¬ÌâÄ¿ÄѶȲ»´ó£¬×¢ÖØ¿¼²éѧÉúµÄÓ¦ÓÃÄÜÁ¦£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÒÔº¬ÓÐAl2O3¡¢Fe2O3µÈÔÓÖʵĸõÌú¿ó[Ö÷Òª³É·ÝΪFe£¨CrO2£©2]ΪÖ÷ÒªÔ­ÁÏÉú²úÖØ¸õËáÄÆ¾§Ì壨Na2Cr2O7?
2H2O£©µÄÖ÷Òª¹¤ÒÕÁ÷³ÌÈçÏ£º

¼ºÖª£º¸õÌú¿óÔÚ¿ÕÆøÖÐÓë´¿¼îìÑÉÕÉú³ÉNa2CrO4ºÍÒ»ÖÖºìרɫ¹ÌÌ壬ͬʱÊͷųöCO2ÆøÌ壬ͬʱAl2O3+Na2CO3 
ȼÉÕ
.
.
2NaAlO2+CO2¡ü£®Çë»Ø´ð£º
£¨1£©ÔÚ¸õÌú¿óFe£¨CrO2£©2ÖУ¬CrµÄ»¯ºÏ¼ÛΪ
 
£®
£¨2£©ÂËÔü1µÄ³É·ÖΪ
 
£¬ÂËÔü2µÄ³É·ÖΪ
 
£®
£¨3£©½«ÂËÔü1·ÅÈëÏ¡ÁòËáÈܽâºóµÃÈÜÒºW£¬¼ìÑé¸ÃÈÜÒºÖнðÊôÀë×ӵķ½·¨ÊÇ
 
£®
£¨4£©¸õÌú¿óÖеÄAl2O3ÔÓÖÊÔÚ¹¤ÒµÉÏ¿ÉÓÃÀ´Ò±Á¶ÂÁ£¬¸Ã»¯Ñ§·½³ÌʽΪ
 
£®
£¨5£©¸ù¾ÝÓйعú¼Ò±ê×¼£¬º¬CrO42-µÄ·ÏˮҪ¾­»¯Ñ§´¦Àí£¬Ê¹ÆäŨ¶È½µÖÁ5.0¡Á10-7mol/LÒÔϲÅÄÜÅÅ·Å£®º¬
CrO42-µÄ·ÏË®´¦Àíͨ³£ÓÐÒÔÏÂÁ½ÖÖ·½·¨£®
¢Ù³Áµí·¨£º¼ÓÈë¿ÉÈÜÐÔ±µÑÎÉú³ÉBaCrO4³Áµí[KSP£¨BaCrO4£©=1.2¡Á10-10]£¬ÔÙ¼ÓÈë¿ÉÈÜÐÔÁòËáÑδ¦Àí¶àÓàµÄ
Ba2+£®¼ÓÈë¿ÉÈÜÐÔ±µÑκóµÄ·ÏË®ÖÐBa2+µÄŨ¶ÈÓ¦²»Ð¡ÓÚ
 
mol/L£¬ºóÐø·ÏË®´¦Àí·½ÄÜ´ïµ½¹ú¼ÒÅŷűê×¼£®
¢Ú»¹Ô­·¨£ºCrO42-
ÂÌ·¯
H+
Cr
ʯ»ÒË®
Cr£¨OH£©3£®Ð´³öËáÐÔÌõ¼þÏÂCrO42-ÓëÂÌ·¯ÔÚÈÜÒºÖз´Ó¦µÄÀë×Ó·½³Ìʽ
 
£®
£¨6£©Ä³¸ßЧ¾»Ë®¼ÁÊÇÓÉK2FeO4µÃµ½µÄ£¬¹¤ÒµÉÏÒÔÈÜÒºW¡¢´ÎÂÈËá¼ØºÍÇâÑõ»¯¼ØÎªÔ­ÁÏÖÆ±¸K2FeO4£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
 
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø