ÌâÄ¿ÄÚÈÝ

2£®ÊµÑéÊÇѧϰ»¯Ñ§µÄ»ù±¾·½·¨£¬Çë»Ø´ðÏÂÁÐÓйØÎÊÌ⣺
£¨1£©ÅäÖÃ500mL0.1mol•L-1µÄNaOHÈÜÒº£¬ÐèÒªÓõ½µÄ²£Á§ÒÇÆ÷ÓУºÉÕ±­¡¢Á¿Í²¡¢²£Á§°ô¡¢500mLÈÝÁ¿Æ¿¡¢½ºÍ·µÎ¹Ü£®
£¨2£©´ÓµâË®ÖÐÝÍÈ¡µâ£¬³£ÓõÄÝÍÈ¡¼ÁÊÇ£º±½»òËÄÂÈ»¯Ì¼£®
£¨3£©Ëá¼îÖк͵ζ¨ÖУ¬ÏÂÁвÙ×÷»áµ¼Ö½á¹ûÆ«¸ßµÄÊÇB£®
A£®µÎ¶¨¹ÜÏ´¾»ºóδÈóÏ´¾ÍÖ±½ÓÓÃÓÚÊ¢×°´ý²âÒº
B£®µÎ¶¨Ê±£¬±ê×¼Òº½¦Âäµ½×¶ÐÎÆ¿Íâ
C£®Ê¢×°´ý²âÒºµÄµÎ¶¨¹ÜÖУ¬¿ªÊ¼ÓÐÆøÅÝȡҺ¹ý³ÌÖÐÆøÅÝÏûʧ
D£®¶Ô±ê×¼Òº½øÐжÁÊýʱ£¬µÎ¶¨Ç°ÑöÊÓ¡¢µÎ¶¨ºó¸©ÊÓ
£¨4£©Öкͷ´Ó¦·´Ó¦ÈȵIJⶨʵÑé×°ÖÃÈçͼ1Ëùʾ£¬ÔÚ´óÉÕ±­µ×²¿µæÅÝÄ­ËÜÁÏ£¬Ê¹·ÅÈëµÄСÉÕ±­±­¿ÚÓë´óÉÕ±­±­¿ÚÏàÆ½£¬È»ºóÔÙÔÚ´ó¡¢Ð¡ÉÕ±­Ö®¼äÌîÂúÅÝÄ­ËÜÁÏ£¬´óÉÕ±­ÉÏÓÃÅÝÄ­ËÜÁϰå×÷¸Ç°å£¬ÔÚ°åÖм俪Á½¸öС¿×£¬ÕýºÃʹζȼƺͻ·Ðβ£Á§½Á°è°ôͨ¹ý£®ÕâÑù×öµÄÄ¿µÄÊÇ£º±£Î¸ôÈÈ¡¢¼õÉÙʵÑé¹ý³ÌÖÐÈÈÁ¿Ëðʧ£®

£¨5£©Èçͼ2Ëùʾ£¬¸øËé´ÉƬ¼ÓÇ¿ÈÈ£¬Ê¯À¯ÓÍ£¨ÒºÌ¬ÍéÌþ»ìºÏÎÕôÆûͨ¹ý³ãÈȵÄËé´ÉƬ±íÃæ·¢Éú·´Ó¦Éú³ÉÆøÌ壮½«ÆøÌåͨ¹ýËáÐÔ¸ßÃÌËá¼ØÈÜÒº£¬¹Û²ìµ½µÄÏÖÏóÊÇ£º½«ÆøÌåͨ¹ýäåµÄËÄÂÈ»¯Ì¼ÈÜÒºÖУ¬ÈÜÒºÍÊÉ«£®ÈÜÒºÖз¢Éú·´Ó¦µÄ·½³Ìʽ£ºCH2=CH2+Br2¡úCH2Br-CH2Br£®

·ÖÎö £¨1£©¸ù¾ÝʵÑé²½ÖèѡȡʵÑéÒÇÆ÷£»
£¨2£©¸ù¾ÝÝÍȡʱÝÍÈ¡¼ÁµÄÑ¡ÔñÓ¦·ûºÏÏÂÁÐÌõ¼þ£ºÈÜÖÊÔÚÝÍÈ¡¼ÁÖеÄÈܽâ¶È±ÈÔÚÔ­ÈܼÁÖÐÒª´ó£»ÝÍÈ¡¼ÁÓëÔ­ÈܼÁ²»ÏàÈÜ£»ÝÍÈ¡¼ÁÓëÈÜÖʲ»·´Ó¦£»
£¨3£©¸ù¾Ý²Ù×÷¶Ôc£¨´ý²â£©=$\frac{c£¨±ê×¼£©¡ÁV£¨±ê×¼£©}{V£¨´ý²â£©}$µÄÓ°Ïì·ÖÎö£»
£¨4£©ÖкÍÈȲⶨʵÑé³É°ÜµÄ¹Ø¼üÊǾ¡¿ÉÄܼõÉÙÈÈÁ¿µÄɢʧ£¬¾Ý´Ë·ÖÎöÄ¿µÄ£»
£¨5£©Ê¯À¯ÓÍ·Ö½âÉú³ÉÏ©ÌþºÍÍéÌþ£¬Ï©ÌþÄܹ»Óëäå·¢Éú¼Ó³É·´Ó¦£¬Ò²Äܱ»ËáÐÔ¸ßÃÌËá¼ØÑõ»¯£®

½â´ð ½â£º£¨1£©ÅäÖÆ²½ÖèÓУº³ÆÁ¿¡¢ÈÜ½â¡¢ÒÆÒº¡¢Ï´µÓ¡¢¶¨ÈÝ¡¢Ò¡ÔȵȲÙ×÷£¬Ò»°ãÌìÆ½³ÆÁ¿¹ÌÌ壬°ÑNaOHµ¹ÈëÉÕ±­½øÐÐÈܽ⣬ÀäÈ´ºó×ªÒÆµ½500mLÈÝÁ¿Æ¿ÖУ¬²¢Óò£Á§°ôÒýÁ÷£¬µ±¼ÓË®ÖÁÒºÃæ¾àÀë¿Ì¶ÈÏß1¡«2cmʱ£¬¸ÄÓýºÍ·µÎ¹ÜµÎ¼Ó£¬ËùÒÔÐèÒª²£Á§ÒÇÆ÷Óв£Á§°ô¡¢ÉÕ±­¡¢½ºÍ·µÎ¹Ü¡¢500mLÈÝÁ¿Æ¿¡¢Á¿Í²£»
¹Ê´ð°¸Îª£º500mLÈÝÁ¿Æ¿¡¢½ºÍ·µÎ¹Ü£»
£¨2£©µâÔÚ±½»òËÄÂÈ»¯Ì¼ÖеÄÈܽâ¶È´óÓÚÔÚË®ÖеÄÈܽâ¶È£¬ÇÒµâÓë±½»òËÄÂÈ»¯Ì¼²»·´Ó¦£¬Ë®Óë±½»òËÄÂÈ»¯Ì¼²»»¥ÈÜ£»
¹Ê´ð°¸Îª£º±½»òËÄÂÈ»¯Ì¼£»
£¨3£©A£®µÎ¶¨¹ÜÏ´¾»ºóδÈóÏ´¾ÍÖ±½ÓÓÃÓÚÊ¢×°´ý²âÒº£¬µ¼Ö´ý²âҺŨ¶È¼õС£¬ÏûºÄµÄ±ê×¼ÒºÌå»ý¼õС£¬¸ù¾Ýc£¨´ý²â£©=$\frac{c£¨±ê×¼£©¡ÁV£¨±ê×¼£©}{V£¨´ý²â£©}$·ÖÎö£¬²â¶¨½á¹ûÆ«µÍ£¬¹ÊA´íÎó£»
B£®µÎ¶¨Ê±£¬±ê×¼Òº½¦Âäµ½×¶ÐÎÆ¿Í⣬ÏûºÄµÄ±ê×¼ÒºÌå»ýÆ«´ó£¬¸ù¾Ýc£¨´ý²â£©=$\frac{c£¨±ê×¼£©¡ÁV£¨±ê×¼£©}{V£¨´ý²â£©}$·ÖÎö£¬²â¶¨½á¹ûÆ«¸ß£¬¹ÊBÕýÈ·£»
C£®Ê¢×°´ý²âÒºµÄµÎ¶¨¹ÜÖУ¬¿ªÊ¼ÓÐÆøÅÝȡҺ¹ý³ÌÖÐÆøÅÝÏûʧ£¬µ¼Ö´ý²âÒºÎïÖʵÄÁ¿¼õС£¬ÏûºÄµÄ±ê×¼ÒºÌå»ý¼õС£¬¸ù¾Ýc£¨´ý²â£©=$\frac{c£¨±ê×¼£©¡ÁV£¨±ê×¼£©}{V£¨´ý²â£©}$·ÖÎö£¬²â¶¨½á¹ûÆ«µÍ£¬¹ÊC´íÎó£»
D£®¶Ô±ê×¼Òº½øÐжÁÊýʱ£¬µÎ¶¨Ç°ÑöÊÓ¡¢µÎ¶¨ºó¸©ÊÓ£¬ÏûºÄµÄ±ê×¼ÒºÌå»ý¼õС£¬¸ù¾Ýc£¨´ý²â£©=$\frac{c£¨±ê×¼£©¡ÁV£¨±ê×¼£©}{V£¨´ý²â£©}$·ÖÎö£¬²â¶¨½á¹ûÆ«µÍ£¬¹ÊD´íÎó£»
¹ÊÑ¡B£®
£¨4£©Öкͷ´Ó¦·´Ó¦ÈȵIJⶨʵÑé×°ÖÃÈçͼ1Ëùʾ£¬ÕâÑù×öµÄÄ¿µÄÊÇ£º±£Î¸ôÈÈ¡¢¼õÉÙʵÑé¹ý³ÌÖÐÈÈÁ¿Ëðʧ£»
¹Ê´ð°¸Îª£º±£Î¸ôÈÈ¡¢¼õÉÙʵÑé¹ý³ÌÖÐÈÈÁ¿Ëðʧ£»
£¨5£©Ê¯À¯Ó͵ķֽâ²úÎïÖк¬ÓÐÏ©Ìþ£¬Ï©ÌþÄܱ»ËáÐÔ¸ßÃÌËá¼ØÈÜÒºÑõ»¯¶øÊ¹ËáÐÔ¸ßÃÌËá¼ØÈÜÒºÍÊÉ«£¬Ï©ÌþÄܺÍäå·¢Éú¼Ó³É·´Ó¦¶øÊ¹äåË®ÍÊÉ«£¬·½³Ìʽ£ºCH2=CH2+Br2¡úCH2Br-CH2Br£»
¹Ê´ð°¸Îª£ºËáÐÔ¸ßÃÌËá¼ØÈÜÒºÍÊÉ«£»CH2=CH2+Br2¡úCH2Br-CH2Br£®

µãÆÀ ±¾Ì⿼²éÁËÈÜÒºµÄÅäÖÆ£¬Öк͵樵ÄÎó²î·ÖÎöºÍ²Ù×÷£¬·´Ó¦ÈȵIJⶨ¡¢ÓлúÎï½á¹¹ÓëÐÔÖÊ£¬·ÖÎöÎó²îʱҪ¿¼ÂǶԱê×¼ÈÜÒºÌå»ýµÄÓ°Ï죬¸ù¾Ýc£¨´ý²â£©=$\frac{c£¨±ê×¼£©¡ÁV£¨±ê×¼£©}{V£¨´ý²â£©}$ÅжÏÎó²î£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø