ÌâÄ¿ÄÚÈÝ
ÔÚ»ð¼ýÍÆ½øÆ÷ÖÐ×°ÓÐÇ¿»¹Ô¼Áë £¨N2H4£©ºÍÇ¿Ñõ»¯¼Á£¨H2O2£©£¬µ±ËüÃÇ»ìºÏʱ£¬¼´²úÉú´óÁ¿µÄN2ºÍË®ÕôÆø£¬²¢·Å³ö´óÁ¿ÈÈ£®ÒÑÖª0.4molҺ̬ëºÍ×ãÁ¿H2O2·´Ó¦£¬Éú³ÉµªÆøºÍË®ÕôÆø£¬·Å³ö256.65kJµÄÈÈÁ¿£®
£¨1£©Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ £®
£¨2£©ÒÑÖªN2£¨g£©+2O2£¨g£©¨T2NO2£¨g£©£»¡÷H=+67.7kJ?mol-1£¬N2H4£¨g£©+O2£¨g£©¨TN2£¨g£©+2H2O £¨g£©£»¡÷H=-534kJ?mol-1£¬¸ù¾Ý¸Ç˹¶¨ÂÉд³öëÂÓëNO2ÍêÈ«·´Ó¦Éú³ÉµªÆøºÍÆøÌ¬Ë®µÄÈÈ»¯Ñ§·½³Ìʽ £®
£¨1£©Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ
£¨2£©ÒÑÖªN2£¨g£©+2O2£¨g£©¨T2NO2£¨g£©£»¡÷H=+67.7kJ?mol-1£¬N2H4£¨g£©+O2£¨g£©¨TN2£¨g£©+2H2O £¨g£©£»¡÷H=-534kJ?mol-1£¬¸ù¾Ý¸Ç˹¶¨ÂÉд³öëÂÓëNO2ÍêÈ«·´Ó¦Éú³ÉµªÆøºÍÆøÌ¬Ë®µÄÈÈ»¯Ñ§·½³Ìʽ
¿¼µã£ºÈÈ»¯Ñ§·½³Ìʽ
רÌ⣺»¯Ñ§·´Ó¦ÖеÄÄÜÁ¿±ä»¯
·ÖÎö£º£¨1£©0.4molҺ̬ëºÍ×ãÁ¿ÒºÌ¬H2O2·´Ó¦Éú³ÉµªÆøºÍË®ÕôÆøÊ±·Å³ö256.65kJµÄÈÈÁ¿£¬1molҺ̬ëÂÍêÈ«·´Ó¦·Å³öµÄÈÈÁ¿=
=641.625kJ/mol£»
£¨2£©¸ù¾ÝÒÑÖªÈÈ»¯Ñ§·½³Ìʽ£¬ÀûÓøÇ˹¶¨ÂÉÊéд£®
| 256.65KJ |
| 0.4mol |
£¨2£©¸ù¾ÝÒÑÖªÈÈ»¯Ñ§·½³Ìʽ£¬ÀûÓøÇ˹¶¨ÂÉÊéд£®
½â´ð£º
½â£º£¨1£©0.4molҺ̬ëºÍ×ãÁ¿ÒºÌ¬H2O2·´Ó¦Éú³ÉµªÆøºÍË®ÕôÆøÊ±·Å³ö256.65kJµÄÈÈÁ¿£¬1molҺ̬ëÂÍêÈ«·´Ó¦·Å³öµÄÈÈÁ¿=
=641.625kJ/mol£¬ÆäÈÈ»¯Ñ§·´Ó¦·½³ÌʽΪN2H4£¨l£©+2H2O2£¨l£©=N2£¨g£©+4H2O£¨g£©¡÷H=-641.625kJ/mol£¬
¹Ê´ð°¸Îª£ºN2H4£¨l£©+2H2O2£¨l£©=N2£¨g£©+4H2O£¨g£©¡÷H=-641.625kJ/mol£»
£¨2£©¢ÙN2£¨g£©+2O2£¨g£©¨T2NO2£¨g£©£¬¡÷H=+67.7KJ?mol-1£»
¢ÚN2H4£¨g£©+O2£¨g£©¨TN2£¨g£©+2H2O £¨g£©£¬¡÷H=-534KJ?mol-1
½«·½³Ìʽ2¡Á¢Ú-¢ÙµÃ2N2H4£¨g£©+2NO2£¨g£©=3N2£¨g£©+4H2O£¨g£©¡÷H=2£¨-534KJ?mol-1£©-£¨+67.7KJ?mol-1£©=-1135.7kJ?mol-1£¬
¹Ê´ð°¸Îª£º2N2H4£¨g£©+2NO2£¨g£©=3N2£¨g£©+4H2O£¨g£©¡÷H=-1135.7kJ?mol-1£®
| 256.65KJ |
| 0.4mol |
¹Ê´ð°¸Îª£ºN2H4£¨l£©+2H2O2£¨l£©=N2£¨g£©+4H2O£¨g£©¡÷H=-641.625kJ/mol£»
£¨2£©¢ÙN2£¨g£©+2O2£¨g£©¨T2NO2£¨g£©£¬¡÷H=+67.7KJ?mol-1£»
¢ÚN2H4£¨g£©+O2£¨g£©¨TN2£¨g£©+2H2O £¨g£©£¬¡÷H=-534KJ?mol-1
½«·½³Ìʽ2¡Á¢Ú-¢ÙµÃ2N2H4£¨g£©+2NO2£¨g£©=3N2£¨g£©+4H2O£¨g£©¡÷H=2£¨-534KJ?mol-1£©-£¨+67.7KJ?mol-1£©=-1135.7kJ?mol-1£¬
¹Ê´ð°¸Îª£º2N2H4£¨g£©+2NO2£¨g£©=3N2£¨g£©+4H2O£¨g£©¡÷H=-1135.7kJ?mol-1£®
µãÆÀ£º±¾Ì⿼²éÁËÈÈ»¯Ñ§·½³ÌʽÊéдºÍ¸Ç˹¶¨ÂɵÄÓ¦Óã¬ÌâÄ¿ÄѶÈÖеȣ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
X¡¢Y¡¢Z¡¢W¾ùΪÖÐѧ»¯Ñ§Öг£¼ûÎïÖÊ£¬Ò»¶¨Ìõ¼þÏÂËüÃÇÖ®¼äÓÐÈçͼת»¯¹ØÏµ£¨ÆäËü²úÎïÒÑÂÔÈ¥£©£ºÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

| A¡¢ÈôWÊǵ¥ÖÊÌú£¬ÔòZÈÜÒº¿ÉÄÜÊÇFeCl2ÈÜÒº |
| B¡¢ÈôWÊÇÇâÑõ»¯ÄÆ£¬ÔòXË®ÈÜÒº³ÊËáÐÔ |
| C¡¢ÈôWÊÇÑõÆø£¬ÔòX¡¢ZµÄÏà¶Ô·Ö×ÓÖÊÁ¿¿ÉÄÜÏà²î48 |
| D¡¢ÈôWÊÇÇ¿Ñõ»¯ÐԵĵ¥ÖÊ£¬ÔòX¿ÉÄÜÊǽðÊôÂÁ |
ÏÂÁнðÊôÒ±Á¶µÄ·´Ó¦ÔÀí£¬´íÎóµÄÊÇ£¨¡¡¡¡£©
A¡¢2NaCl£¨Ë®ÈÜÒº£©
| ||
B¡¢CuO+H2
| ||
C¡¢Fe3O4+4CO
| ||
D¡¢2HgO
|
| A¡¢·ÅµçʱÕý¼«·´Ó¦Îª£ºNiOOH+H2O+e-=Ni£¨OH£©2+OH- |
| B¡¢·Åµçʱ¸º¼«·´Ó¦Îª£ºMH+OH--2e-=H2O+M+ |
| C¡¢³äµçʱÇâÑõ¸ùÀë×ÓÒÆÏòÑô¼«£¬Òª²ÎÓëµç¼«·´Ó¦ |
| D¡¢³äµçʱµç³ØµÄÕý¼«Á¬½ÓÖ±Á÷µçÔ´µÄÕý¼«£¬µÃµ½µç×Ó·¢Éú»¹Ô·´Ó¦ |
ÏÂÁÐÓйؽðÊô¸¯Ê´Óë·À»¤µÄ˵·¨ÖУ¬²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
| A¡¢Î¶ÈÔ½¸ß£¬½ðÊô¸¯Ê´Ô½¿ì |
| B¡¢½ðÊô±»¸¯Ê´µÄ±¾ÖÊÊÇ·¢ÉúÁËÑõ»¯·´Ó¦ |
| C¡¢½«¸ÖÕ¢ÃÅÓëÖ±Á÷µçÔ´µÄÕý¼«ÏàÁ¬¿É·ÀÖ¹Æä±»¸¯Ê´ |
| D¡¢ÔÚÌú¹ÜÉ϶ÆÐ¿¿É·ÀÖ¹Æä±»¸¯Ê´ |
·ÖÎöÒÔϼ¸¸öÈÈ»¯Ñ§·½³Ìʽ£¬ÄܱíʾȼÉÕÈȵÄÊÇ£¨¡¡¡¡£©
| A¡¢C£¨s£©+O2£¨g£©¨TCO£¨g£©¡÷H=-110.5 kJ/mol | ||
| B¡¢C£¨s£©+O2£¨g£©¨TCO2£¨g£©¡÷H=-393.5 kJ/mol | ||
| C¡¢2H2 £¨g£©+O2£¨g£©¨T2H2O£¨l£©¡÷H=-571.6 kJ/mol | ||
D¡¢H2£¨g£©+
|
ÓÃNA±íʾ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ£¬ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©
| A¡¢28gµªÆøËùº¬ÓеÄÔ×ÓÊýĿΪNA |
| B¡¢»¯Ñ§·´Ó¦ÖÐ1mol½ðÊôþ±ä³ÉþÀë×Óʱʧȥµç×ÓÊýĿΪ2NA |
| C¡¢±ê×¼×´¿öÏ£¬22.4LË®Öк¬ÓиöË®·Ö×ÓNA |
| D¡¢±ê×¼×´¿öÏ£¬22.4LÂÈ»¯ÇâËùº¬µÄÔ×ÓÊýΪNA |
µÈÖÊÁ¿µÄÏÂÁÐÆøÌåËùº¬Ô×ÓÊý×î¶àµÄÊÇ£¨¡¡¡¡£©
| A¡¢C2H6 |
| B¡¢CH4 |
| C¡¢CO |
| D¡¢H2 |