ÌâÄ¿ÄÚÈÝ
£¨1£©Èçͼ1Ëùʾˮ²ÛÖÐÊÔ¹ÜÄÚÓÐһöÌú¶¤£¬·ÅÖÃÊýÌì·¢ÏÖÊÔ¹ÜÄÚÒºÃæÏ½µ£¬ÔòÔÈÜÒº³Ê
£¨2£©¸ÖÌúºÜÈÝÒ×ÉúÐâ¶ø±»¸¯Ê´£¬Ã¿ÄêÒò¸¯Ê´¶øËðʧµÄ¸Ö²ÄÕ¼ÊÀ½ç¸ÖÌúÄê²úÁ¿µÄËÄ·ÖÖ®Ò»£®ÔÚʵ¼ÊÉú²úÖУ¬¿ÉÔÚÌú¼þµÄ±íÃæ¶ÆÍ·ÀÖ¹Ìú±»¸¯Ê´£®×°ÖÃʾÒâͼÈç2£º
Çë»Ø´ð£º¢ÙAµç¼«Îª
¢ÚÈôµç¶ÆÇ°Ìú¡¢ÍÁ½µç¼«µÄÖÊÁ¿Ïàͬ£¬µç¶ÆÍê³Éºó½«ËüÃÇÈ¡³öÏ´¾»¡¢ºæ¸É¡¢³ÆÁ¿£¬
¶þÕßÖÊÁ¿²îΪ5.12g£¬Ôòµç¶ÆÊ±µç·ÖÐͨ¹ýµÄµç×ÓΪ
¢Û¶Æ²ãÆÆËðºó£¬¶ÆÍÌú±È¶ÆÐ¿Ìú¸üÈÝÒ×±»¸¯Ê´£¬Çë¼òҪ˵Ã÷ÔÒò£®
£¨3£©Ä¿Ç°ÎÒ¹úÐí¶à´óÐÍÍÖÊÎÄÎï¶Ìì·ÅÖø¯Ê´ÑÏÖØ£¬ÔÚ²»Ó°Ïì¹ÛհЧ¹ûµÄÌõ¼þÏ£¬³ýÓüӱ£»¤²ã·¨±£»¤Í⣬ÇëÄãÔÙÌá³öÒ»Ïî¼òµ¥¶øÓÐЧµÄ±£»¤·½·¨
¿¼µã£ºÌ½¾¿ÌúµÄÎüÑõ¸¯Ê´
רÌ⣺µç»¯Ñ§×¨Ìâ
·ÖÎö£º£¨1£©¸ù¾ÝÊÔ¹ÜÄÚÒºÃæÏ½µ£¬ËµÃ÷ÊÔ¹ÜÖÐÆøÌåÔö¼Ó£¬Ôò·¢ÉúÁËÎöÇⸯʴ£¬Õý¼«ÉÏÇâÀë×ӵõç×ÓÉú³ÉÇâÆø£»
£¨2£©¢Ùµç¶ÆÊ±£¬¶Æ²ã×÷Ñô¼«£¬¶Æ¼þ×÷Òõ¼«£¬Òõ¼«Éϵõç×Ó·¢Éú»¹Ô·´Ó¦£»
¢ÚÑô¼«ÉÏÍʧµç×Ó·¢ÉúÑõ»¯·´Ó¦£¬Òõ¼«ÉÏÍÀë×ӵõç×Ó·¢Éú»¹Ô·´Ó¦£¬Èôµç¶ÆÇ°Ìú¡¢ÍÁ½Æ¬½ðÊôÖÊÁ¿Ïàͬ£¬µç¶ÆÍê³Éºó¶þÕßÖÊÁ¿²îΪ5.12g£¬¶þÕßÖÊÁ¿²îµÄÒ»°ëΪÒõ¼«Îö³öµÄÍ£¬¸ù¾ÝͺÍ×ªÒÆµç×ÓÖ®¼äµÄ¹ØÏµÊ½¼ÆË㣻
¢Û×÷Ôµç³Ø¸º¼«µÄÌúÒ×±»¸¯Ê´£»
£¨3£©ÀûÓÃÔµç³Ø¹¤×÷ÔÀíÉè¼Æ±£»¤´óÐÍÍÖÊÎÄÎïµÄ¼òµ¥¶øÓÐЧµÄ·½·¨£®
£¨2£©¢Ùµç¶ÆÊ±£¬¶Æ²ã×÷Ñô¼«£¬¶Æ¼þ×÷Òõ¼«£¬Òõ¼«Éϵõç×Ó·¢Éú»¹Ô·´Ó¦£»
¢ÚÑô¼«ÉÏÍʧµç×Ó·¢ÉúÑõ»¯·´Ó¦£¬Òõ¼«ÉÏÍÀë×ӵõç×Ó·¢Éú»¹Ô·´Ó¦£¬Èôµç¶ÆÇ°Ìú¡¢ÍÁ½Æ¬½ðÊôÖÊÁ¿Ïàͬ£¬µç¶ÆÍê³Éºó¶þÕßÖÊÁ¿²îΪ5.12g£¬¶þÕßÖÊÁ¿²îµÄÒ»°ëΪÒõ¼«Îö³öµÄÍ£¬¸ù¾ÝͺÍ×ªÒÆµç×ÓÖ®¼äµÄ¹ØÏµÊ½¼ÆË㣻
¢Û×÷Ôµç³Ø¸º¼«µÄÌúÒ×±»¸¯Ê´£»
£¨3£©ÀûÓÃÔµç³Ø¹¤×÷ÔÀíÉè¼Æ±£»¤´óÐÍÍÖÊÎÄÎïµÄ¼òµ¥¶øÓÐЧµÄ·½·¨£®
½â´ð£º
½â£º£¨1£©ÈôÊÔ¹ÜÄÚÒºÃæÏ½µ£¬ËµÃ÷½ðÊôµÄ¸¯Ê´ÖÐÉú³ÉÆøÌåµ¼ÖÂѹǿÔö´ó£¬Ôò½ðÊô·¢ÉúµÄÊÇÎöÇⸯʴ£¬ÈÜÒº³ÊËáÐÔ£¬¸º¼«ÉÏÌúʧµç×Ó·¢ÉúÑõ»¯·´Ó¦£¬µç¼«·´Ó¦Ê½Îª£ºFe-2e-=Fe2+£¬Õý¼«ÉÏÇâÀë×ӵõç×Ó·¢Éú»¹Ô·´Ó¦£¬µç¼«·´Ó¦Ê½Îª£ºH++2e-=H2¡ü£¬
¹Ê´ð°¸Îª£º½ÏÇ¿µÄË᣻ÎöÇ⣻H++2e-=H2¡ü£»
£¨2£©¢ÙÔÚÌú¼þµÄ±íÃæ¶ÆÍµÄµç¶Æ³ØÖУ¬×÷Ñô¼«µÄÊǶƲã½ðÊôÍ£»ÔÚÌú¼þµÄ±íÃæ¶ÆÍµÄµç¶Æ³ØÖУ¬×öÒõ¼«µÄÊÇ´ý¶Æ½ðÊôÌú£¬¸Ã¼«ÉϽðÊôÑôÀë×ÓÍÀë×Ó·¢ÉúµÃµç×ӵĻ¹Ô·´Ó¦£¬¼´Cu2++2e-=Cu£¬
¹Ê´ð°¸Îª£ºÍ£»Cu2++2e-=Cu£»
¢ÚÑô¼«ÉÏÍʧµç×Ó·¢ÉúÑõ»¯·´Ó¦£¬Òõ¼«ÉÏÍÀë×ӵõç×Ó·¢Éú»¹Ô·´Ó¦£¬Èôµç¶ÆÇ°Ìú¡¢ÍÁ½Æ¬½ðÊôÖÊÁ¿Ïàͬ£¬µç¶ÆÍê³Éºó¶þÕßÖÊÁ¿²îΪ5.12g£¬¶þÕßÖÊÁ¿²îµÄÒ»°ëΪÒõ¼«Îö³öµÄÍ£¬Ôò×ªÒÆµç×ÓµÄÎïÖʵÄÁ¿Îª£º
=0.08mol£¬
¹Ê´ð°¸Îª£º0.08£»
¢Û¶ÆÍÌúÆÆËðºó£¬½ðÊôÌúΪ¸º¼«£¬¶ÆÐ¿ÌúÆÆËðºó£¬½ðÊôÌúÊÇÕý¼«£¬ÔÚÔµç³ØÖУ¬¸º¼«½ðÊô¸üÒ×±»¸¯Ê´£¬ËùÒÔ¶ÆÍÌú±È¶ÆÐ¿Ìú¸üÈÝÒ×±»¸¯Ê´£¬
¹Ê´ð°¸Îª£ºÌú±ÈÍ»îÆÃ£¬¶Æ²ãÆÆ»µºó£¬ÔÚ³±Êª»·¾³ÖÐÐγÉÔµç³Ø£¬ÌúΪ¸º¼«£¬¼ÓËÙÌúµÄ¸¯Ê´£»
£¨3£©¸ù¾ÝÔµç³ØÔÀí£¬½«ÍÖÊÎÄÎïÁ¬½ÓÌú¿é£¬Ôò¸¯Ê´¹ý³ÌÖÐÌúΪ¸º¼«£¬ÍΪÕý¼«£¬ÔòÆðµ½Á˱£»¤ÎÄÎïµÄЧ¹û£¬
¹Ê´ð°¸Îª£º½«Ìú¿éÁ¬½ÓÎÄÎïµ××ù²¢ÂñÓÚµØÏ£¬¶¨ÆÚ¸ü»»£®
¹Ê´ð°¸Îª£º½ÏÇ¿µÄË᣻ÎöÇ⣻H++2e-=H2¡ü£»
£¨2£©¢ÙÔÚÌú¼þµÄ±íÃæ¶ÆÍµÄµç¶Æ³ØÖУ¬×÷Ñô¼«µÄÊǶƲã½ðÊôÍ£»ÔÚÌú¼þµÄ±íÃæ¶ÆÍµÄµç¶Æ³ØÖУ¬×öÒõ¼«µÄÊÇ´ý¶Æ½ðÊôÌú£¬¸Ã¼«ÉϽðÊôÑôÀë×ÓÍÀë×Ó·¢ÉúµÃµç×ӵĻ¹Ô·´Ó¦£¬¼´Cu2++2e-=Cu£¬
¹Ê´ð°¸Îª£ºÍ£»Cu2++2e-=Cu£»
¢ÚÑô¼«ÉÏÍʧµç×Ó·¢ÉúÑõ»¯·´Ó¦£¬Òõ¼«ÉÏÍÀë×ӵõç×Ó·¢Éú»¹Ô·´Ó¦£¬Èôµç¶ÆÇ°Ìú¡¢ÍÁ½Æ¬½ðÊôÖÊÁ¿Ïàͬ£¬µç¶ÆÍê³Éºó¶þÕßÖÊÁ¿²îΪ5.12g£¬¶þÕßÖÊÁ¿²îµÄÒ»°ëΪÒõ¼«Îö³öµÄÍ£¬Ôò×ªÒÆµç×ÓµÄÎïÖʵÄÁ¿Îª£º
| ||
| 64g/mol |
¹Ê´ð°¸Îª£º0.08£»
¢Û¶ÆÍÌúÆÆËðºó£¬½ðÊôÌúΪ¸º¼«£¬¶ÆÐ¿ÌúÆÆËðºó£¬½ðÊôÌúÊÇÕý¼«£¬ÔÚÔµç³ØÖУ¬¸º¼«½ðÊô¸üÒ×±»¸¯Ê´£¬ËùÒÔ¶ÆÍÌú±È¶ÆÐ¿Ìú¸üÈÝÒ×±»¸¯Ê´£¬
¹Ê´ð°¸Îª£ºÌú±ÈÍ»îÆÃ£¬¶Æ²ãÆÆ»µºó£¬ÔÚ³±Êª»·¾³ÖÐÐγÉÔµç³Ø£¬ÌúΪ¸º¼«£¬¼ÓËÙÌúµÄ¸¯Ê´£»
£¨3£©¸ù¾ÝÔµç³ØÔÀí£¬½«ÍÖÊÎÄÎïÁ¬½ÓÌú¿é£¬Ôò¸¯Ê´¹ý³ÌÖÐÌúΪ¸º¼«£¬ÍΪÕý¼«£¬ÔòÆðµ½Á˱£»¤ÎÄÎïµÄЧ¹û£¬
¹Ê´ð°¸Îª£º½«Ìú¿éÁ¬½ÓÎÄÎïµ××ù²¢ÂñÓÚµØÏ£¬¶¨ÆÚ¸ü»»£®
µãÆÀ£º±¾Ì⿼²éÁ˽ðÊôµÄ¸¯Ê´Óë·À»¤¡¢Ôµç³Ø¹¤×÷ÔÀí£¬ÌâÄ¿ÄѶÈÖеȣ¬×¢ÒâÕÆÎÕÔµç³Ø¹¤×÷ÔÀí£¬Ã÷È·½ðÊôµÄ¸¯Ê´Óë·À»¤µÄ·½·¨£¬ÊÔÌâÅàÑøÁËѧÉúÁé»îÓ¦ÓÃËùѧ֪ʶµÄÄÜÁ¦£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÏÂÁи÷×éÎïÖÊÖ®¼äÊÇͬϵÎïµÄÊÇ£¨¡¡¡¡£©
| A¡¢CH3CH2COOHÓëCH3COOCH3 |
| B¡¢ |
| C¡¢2¡¢2-¶þ¼×»ù±ûÍéÓë2-¼×»ù¶¡Íé |
| D¡¢ |
ÏÂÁз´Ó¦ÖУ¬²úÉúÇâÆøËÙ¶È×î¿ìµÄÊÇ£¨¡¡¡¡£©
| A¡¢³£ÎÂÏÂÂÁÓë6mol/LµÄÏõËá |
| B¡¢³£ÎÂÏÂþÓë3mol/LµÄ´×Ëá |
| C¡¢³£ÎÂÏÂÌúÓë3mol/LµÄÑÎËá |
| D¡¢³£ÎÂÏÂþÓë3mol/LµÄÁòËá |
ÔÚÈÜÒºÖеĵçÀë·½³ÌʽÊéдÕýÈ·µÄÊÇ£¨¡¡¡¡£©
| A¡¢H2CO3?2H++CO32- |
| B¡¢CH3COOH=CH3COO-+H+ |
| C¡¢BaCO3?Ba 2++CO32- |
| D¡¢HCO3 -+H2O?CO32-+H3O+ |