题目内容
(1)计算:| 6 |
| m(m-3) |
| 2 |
| m-3 |
(2)化简:(-
| a |
| b |
| c |
| a |
| c |
| b |
分析:(1)首先通分,然后利用同分母的分式相加减的运算法则求解即可求得答案,注意结果需化简;
(2)首先利用乘方运算,求得(-
)2与(-
)3的值,然后利用乘除法运算的法则,求解即可求得答案.
(2)首先利用乘方运算,求得(-
| a |
| b |
| c |
| a |
解答:解:(1)
-
=
-
=
=
=-
;
(2)(-
)2•(-
)3÷(-
)=
•(-
)•(-
)=
.
| 6 |
| m(m-3) |
| 2 |
| m-3 |
| 6 |
| m(m-3) |
| 2m |
| m(m-3) |
| 6-2m |
| m(m-3) |
| 2(3-m) |
| m(m-3) |
| 2 |
| m |
(2)(-
| a |
| b |
| c |
| a |
| c |
| b |
| a2 |
| b2 |
| c3 |
| a3 |
| b |
| c |
| c2 |
| ab |
点评:此题考查了分式的加减与乘除运算法则.此题比较简单,解题的关键是注意准确运用运算法则,注意结果要化为最简.
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