题目内容
利用分解因式的方法计算:
(1)16.8×
+7.6×
(2)(255+511)÷30.
(1)16.8×
| 7 |
| 32 |
| 7 |
| 16 |
(2)(255+511)÷30.
分析:(1)先将原式变形为8.4×2×
+7.6×
,然后变形为8.4×
+7.6×
,利用提公因式法就可以求出其解.
(2)原式变形为(510+511)÷30,再化为510×(1+5)×
,得到510×6×
=510×5-1=59,从而得出结果.
| 7 |
| 32 |
| 7 |
| 16 |
| 7 |
| 16 |
| 7 |
| 16 |
(2)原式变形为(510+511)÷30,再化为510×(1+5)×
| 1 |
| 30 |
| 1 |
| 30 |
解答:解:(1)原式=8.4×2×
+7.6×
,
=8.4×
+7.6×
=
(8.4+7.6),
=7
(2)原式=(510+511)÷30,
=510×(1+5)×
,
=510×6×
=510×5-1
=59.
| 7 |
| 32 |
| 7 |
| 16 |
=8.4×
| 7 |
| 16 |
| 7 |
| 16 |
=
| 7 |
| 16 |
=7
(2)原式=(510+511)÷30,
=510×(1+5)×
| 1 |
| 30 |
=510×6×
| 1 |
| 30 |
=510×5-1
=59.
点评:本题考查了因式分解法在实数的计算中的运用,涉及了同底数幂相乘的法则,提公因式法的运用.
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