题目内容
(1)化简:
×
÷
;
(2)
-
-
;
(3)解方程:(x-1)(x+3)=5;
(4)x2-4x-12=0(用求根公式).
| 75 |
| ||
| 3 |
| 1 | ||
|
(2)
| 4 | ||
4-
|
| 4 | ||||
|
| 2 | ||
3+
|
(3)解方程:(x-1)(x+3)=5;
(4)x2-4x-12=0(用求根公式).
(1)
×
÷
=5
×
×
=10;
(2)
-
-
=
-
-
=
+
-
-
-3+
=
-
;
(3)(x-1)(x+3)=5,
x2+2x-3=5,
x2+2x-8=0,
(x+4)(x-2)=0,
x+4=0或x-2=0,
x1=-4,x2=2;
(4)x2-4x-12=0,
∵a=1,b=-4,c=-12,
b2-4ac=16-4×1×(-12)=64>0,
∴x=
=
,
∴x1=6,x2=-2
| 75 |
| ||
| 3 |
| 1 | ||
|
=5
| 3 |
| ||
| 3 |
| 2 |
=10;
(2)
| 4 | ||
4-
|
| 4 | ||||
|
| 2 | ||
3+
|
=
4(4+
| ||
| 5 |
4(
| ||||
| 4 |
2(3-
| ||
| 2 |
=
| 16 |
| 5 |
4
| ||
| 5 |
| 11 |
| 7 |
| 7 |
=
| 1 |
| 5 |
9
| ||
| 5 |
(3)(x-1)(x+3)=5,
x2+2x-3=5,
x2+2x-8=0,
(x+4)(x-2)=0,
x+4=0或x-2=0,
x1=-4,x2=2;
(4)x2-4x-12=0,
∵a=1,b=-4,c=-12,
b2-4ac=16-4×1×(-12)=64>0,
∴x=
4±
| ||
| 2 |
| 4±8 |
| 2 |
∴x1=6,x2=-2
练习册系列答案
相关题目