题目内容
计算：（1）
÷
×
（2）(
-x+1)÷
．
| x+2 |
| x2-6x+9 |
| 1 |
| 3-x |
| x-3 |
| x+2 |
| x2-1 |
| x2-2x+1 |
| x |
| x-1 |
（1）
÷
×
=
×（3-x）×
=-1；
（2）(
-x+1)÷
=[
-
]×
=
×
=-x+3．
| x+2 |
| x2-6x+9 |
| 1 |
| 3-x |
| x-3 |
| x+2 |
=
| x+2 |
| (x-3)2 |
| x-3 |
| x+2 |
=-1；
（2）(
| x2-1 |
| x2-2x+1 |
| x |
| x-1 |
=[
| (x-1)(x+1) |
| (x-1)2 |
| (x-1)2 |
| x-1 |
| x-1 |
| x |
=
| -x2+3x |
| x-1 |
| x-1 |
| x |
=-x+3．
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