题目内容
(1)(-3
)-3-(2
)-1+(-
)2
(2)[(0.1)-2+(0.01)-1]×(-
)-3
(3)(3x-2)-1÷(
x)-2•(
)2
(4)(a-2-b-2)÷(a-1-b-1)
(5)x-2y-2÷(x-2-y-2)
(6)(2x-2+y)2-(2x-2-y)2.
| 3 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
(2)[(0.1)-2+(0.01)-1]×(-
| 1 |
| 10 |
(3)(3x-2)-1÷(
| 1 |
| 2 |
| 3y-1 |
| 2x |
(4)(a-2-b-2)÷(a-1-b-1)
(5)x-2y-2÷(x-2-y-2)
(6)(2x-2+y)2-(2x-2-y)2.
(1)(-3
)-3-(2
)-1+(-
)2
=-
+
+
=
;
(2)[(0.1)-2+(0.01)-1]×(-
)-3
=[100+100]×(-1000)
=200×(-1000)
=-200000;
(3)(3x-2)-1÷(
x)-2•(
)2
=
•
•
=
;
(4)(a-2-b-2)÷(a-1-b-1)
=(
-
)÷(
-
)
=
•
=
;
(5)x-2y-2÷(x-2-y-2)
=
÷(
-
)
=
÷
=
;
(6)(2x-2+y)2-(2x-2-y)2.
=4x-4+2x-2y+y2-(4x-4-2x-2y+y2)
=4x-4+2x-2y+y2-4x-4+2x-2y-y2
=4x-2y.
| 3 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
=-
| 64 |
| 3375 |
| 2 |
| 5 |
| 1 |
| 4 |
=
| 8519 |
| 13500 |
(2)[(0.1)-2+(0.01)-1]×(-
| 1 |
| 10 |
=[100+100]×(-1000)
=200×(-1000)
=-200000;
(3)(3x-2)-1÷(
| 1 |
| 2 |
| 3y-1 |
| 2x |
=
| x2 |
| 3 |
| x2 |
| 4 |
| 9 |
| 4x2y2 |
=
| 3x2 |
| 16y2 |
(4)(a-2-b-2)÷(a-1-b-1)
=(
| 1 |
| a2 |
| 1 |
| b2 |
| 1 |
| a |
| 1 |
| b |
=
| (b+a)(b-a) |
| a2b2 |
| ab |
| b-a |
=
| a+b |
| ab |
(5)x-2y-2÷(x-2-y-2)
=
| 1 |
| x2y2 |
| 1 |
| x2 |
| 1 |
| y2 |
=
| 1 |
| x2y2 |
| y2-x2 |
| x2y2 |
=
| 1 |
| (y+x)(y-x) |
(6)(2x-2+y)2-(2x-2-y)2.
=4x-4+2x-2y+y2-(4x-4-2x-2y+y2)
=4x-4+2x-2y+y2-4x-4+2x-2y-y2
=4x-2y.
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