题目内容
在Rt△ABC中,∠C=90°,sinA=
,a是∠A的对边.
(1)求tanA;
(2)当a=12cm,求S△ABC.
| 4 |
| 5 |
(1)求tanA;
(2)当a=12cm,求S△ABC.
(1)如图,sinA=
=
,设AB=5k,BC=4k,则AC=3k,tanA=
=
=
.
(2)sinA=
,a=BC=12,则AB=15,AC2=AB2-BC2,AC=9,
S△ABC=
×BC×AC=
×9×12=54(cm2).

| 4 |
| 5 |
| BC |
| AB |
| BC |
| AC |
| 4k |
| 3k |
| 4 |
| 3 |
(2)sinA=
| 4 |
| 5 |
S△ABC=
| 1 |
| 2 |
| 1 |
| 2 |
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