题目内容
对于正数x,规定f(x)=
,例如f(3)=
=
,f(
)=
=
,计算f(
)+f(
)+f(
)+…+f(
)+f(
)+f(1)+f(1)+f(2)+f(3)+…+f(n-2)+f(n-1)+f(n)=______ (n为正整数)
| x |
| 1+x |
| 3 |
| 1+3 |
| 3 |
| 4 |
| 1 |
| 3 |
| ||
1+
|
| 1 |
| 4 |
| 1 |
| n |
| 1 |
| n-1 |
| 1 |
| n-2 |
| 1 |
| 3 |
| 1 |
| 2 |
原式=
+
+
+…+
+
+
+
+
+…+
+
=1+1+…+1
=n.
故答案为:n.
| 1 |
| n+1 |
| 1 |
| n |
| 1 |
| n-1 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 4 |
| n-1 |
| n |
| n |
| n+1 |
=1+1+…+1
=n.
故答案为:n.
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