题目内容
| 3 |
| 1+a |
| 6 |
| 1-a |
| 12 |
| a2-1 |
原式=
+
-
=
=
=
．
| 3(a-1) |
| (a+1)(a-1) |
| 6(a+1) |
| (a+1)(a-1) |
| 12 |
| (a+1)(a-1) |
=
| 3(a-1)+6(a+1)-12 |
| (a+1)(a-1) |
=
| 9(a-1) |
| (a+1)(a-1) |
=
| 9 |
| a+1 |
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