题目内容
计算:
(1)
-
=______;
(2)
+
-
=______;
(3)
-
=______;
(4)
+
=______.
(1)
3a |
3a-2b |
2b |
3a-2b |
(2)
a+2b |
a-b |
b |
b-a |
2a |
a-b |
(3)
x |
(x-1)2 |
1 |
(x-1)2 |
(4)
x2-1 |
x2+2x+1 |
2 |
x+1 |
(1)原式=
=1;
(2)原式=
=
=-1;
(3)原式=
=
;
(4)原式=
+
=
=
=1.
故答案为:(1)1;(2)-1;(3)
;(4)1
3a-2b |
3a-2b |
(2)原式=
a+2b-b-2a |
a-b |
-(a-b) |
a-b |
(3)原式=
x-1 |
(x-1)2 |
1 |
x-1 |
(4)原式=
(x+1)(x-1) |
(x+1)2 |
2 |
x+1 |
x-1+2 |
x+1 |
x+1 |
x+1 |
故答案为:(1)1;(2)-1;(3)
1 |
x-1 |
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