题目内容
化简:(| 1 |
| x-1 |
| x+1 |
| 1-x |
| x2-x |
| x-1 |
| x |
| x-1 |
分析:首先分别利用通分计算每一个括号,然后打开括号计算分式的除法即可求解.
解答:解:(
+
)÷(
+
)
=
÷
=-
.
| 1 |
| x-1 |
| x+1 |
| 1-x |
| x2-x |
| x-1 |
| x |
| x-1 |
=
| 1-x-1 |
| x-1 |
| x2-x+x |
| x-1 |
=-
| 1 |
| x |
点评:此题主要考查了分式的混合运算,解题的关键是熟练掌握分式混合运算法则即可解决问题.
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